无法将as3代码（数组）移植到c＃（列表？）

Question

我试图移植此代码： http://www.emanueleferonato.com/2008/12/08/perfect-maze-generation-tile-based-version-as3/ 到c＃，用XNA编写。

但我迷失了迷宫：

我是c＃的新手，也许有人可以帮助我？

这是我的C＃代码（我删除了绘制方法）：

class Maze 
{
    private int MAZE_WIDTH = 30;
    private int MAZE_HEIGHT = 30;
    private int TILE_SIZE = 10;

    private int _width;
    private int _height;
    private int [,] _maze;
    private List<int> _moves;

    private int _startX;
    private int _startY;
    private int _finishX;
    private int _finishY;

    public Maze()
    {
        _width = MAZE_WIDTH *2 - 1;
        _height = MAZE_HEIGHT *2 - 1;
        _startX = 1;
        _startY = 1;
        _finishX = _height - 2;
        _finishY = _height - 2;

        Generate();
    }

    public void Generate()
    {
        InitMaze();
        CreateMaze();
    }

    private void InitMaze()
    {
        _maze = new int[_width, _height];
        for (var x = 0; x < _height; x++)
        {                                
            for (var y = 0; y < _width; y++)
                _maze[x, y] = 1;
        }

        _maze[_startX, _startY] = 0;
    }


    private void CreateMaze()
    {
        var posX = _startX;
        var posY = _startY;
        _moves = new List<int>();
        _moves.Add(posY + (posX*_width));


        while (_moves.Count > 0)
        {
            string possibleDirections = "";

            if ((posX + 2 < _height) && (_maze[posX + 2, posY] == 1) && (posY + 2 != 0) && (posX + 2 != _height - 1))
            {
                possibleDirections += "S";
            }
            if ((posX - 2 >= 0) && (_maze[posX - 2, posY] == 1) && (posX - 2 != 0) && (posX - 2 != _height - 1))
            {
                possibleDirections += "N";
            }
            if ((posY - 2 >= 0) && (_maze[posX, posY - 2] == 1) && (posY - 2 != 0) && (posY - 2 != _width - 1))
            {
                possibleDirections += "W";
            }
            if ((posY + 2 < _width) && (_maze[posX, posY + 2] == 1) && (posY + 2 != 0) && (posY + 2 != _width - 1))
            {
                possibleDirections += "E";
            }


            if (possibleDirections.Length > 0)
            {

                var move = Utils.RandInt(0, (possibleDirections.Length - 1));

                switch (possibleDirections[move].ToString())
                {
                    case "N":
                        _maze[posX - 2, posY] = 0;
                        _maze[posX - 1, posY] = 0;
                        posX -= 2;
                        break;
                    case "S":
                        _maze[posX + 2, posY] = 0;
                        _maze[posX + 1, posY] = 0;
                        posX += 2;
                        break;
                    case "W":
                        _maze[posX,posY - 2] = 0;
                        _maze[posX,posY - 1] = 0;
                        posY -= 2;
                        break;
                    case "E":
                        _maze[posX,posY + 2] = 0;
                        _maze[posX,posY + 1] = 0;
                        posY += 2;
                        break;
                }
            }
            else
            {
                var back = _moves[_moves.Count - 1];
                _moves.RemoveAt(_moves.Count - 1);

                posX = back/_width;
                posY = back%_width;
            }
        }            
    }


    public void DrawMaze(ScreenBase screen)
    {
        //just drawing tiles
    }

    private int RandInt(int min, int max)
    {
        return new Random().Next(min, max);
    }

    //End of class
}



class Utils
{

    private static readonly Random rnd = new Random();
    public static int RandInt(int min, int max)
    {
        return rnd.Next(min, max);
    }
}

Answer 1

您每次拨打Random时都会生成一个新的RandInt()对象。当它快速连续发生时，它使用相同的种子，因为它基于系统时间，你最终得到相同的＆＃34;随机＆＃34;价值一遍又一遍。

修复它的一种方法是添加另一个字段：

private Random _random = new Random();

然后将您的RandInt()方法更改为：

private int RandInt(int min, int max)
{
    return _random.Next(min, max);
}