Question

我想把这个unicode字符串列表解析成一个表：

[u'$760,507,625 (USA) (18 November 2010)', u'$760,505,847 (USA) (14 November 2010)', u'$760,462,559 (USA) (7 November 2010)', u'$760,410,799 (USA) (31 October 2010)',

所以我想要的结果是：

[[760507625, 11, 18, 2010, 'USA'], 
 [760505847, 11, 7, 2010, 'USA'],
  ....
]

如您所见，格式为[金钱，月，日，年，国家]

也许你可以提供可以解决这个问题的工具。我让我清楚了吗？非常感谢！

Answer 1

我要处理的常用方法是使用正则表达式从每行中取出字段，然后为每个字段添加一行或两行以将其转换为所需格式。这不是万无一失的 - 例如，如果一行有一个错误拼写的月份的条目，它就会崩溃 - 但这对于大多数临时任务来说都足够了。

#!/usr/bin/env python2.7

import re

data = [u'$760,507,625 (USA) (18 November 2010)',
        u'$760,505,847 (USA) (14 November 2010)',
        u'$760,462,559 (USA) (7 November 2010)',
        u'$760,410,799 (USA) (31 October 2010)',
       'blah']

RE_DATA = re.compile(r'^\$([0-9,]+) \(([A-Z]+)\) \(([0-9]+) ([A-Za-z]+) ([0-9]+)\)$')

MONTHS = {
    'January': 1,
    'February': 2,
    'March': 3,
    'April': 4,
    'May': 5,
    'June': 6,
    'July': 7,
    'August': 8,
    'September': 9,
    'October': 10,
    'November': 11,
    'December': 12
}

for entry in data:
    match = RE_DATA.match(entry)
    if match is None:
        print 'Error! %r did not match pattern' % entry
        continue

    amount, country, day, month, year = match.groups()
    amount = int(amount.replace(',', ''))
    country = str(country)
    day = int(day)
    month = MONTHS[month]
    year = int(year)

    print [amount, month, day, year, country]

打印：

[760507625, 11, 18, 2010, 'USA']
[760505847, 11, 14, 2010, 'USA']
[760462559, 11, 7, 2010, 'USA']
[760410799, 10, 31, 2010, 'USA']
Error! 'blah' did not match pattern

如何解析此unicode字符串列表

1 个答案: