我为整数创建了一个数组冒泡排序函数,它与正整数完美匹配,但在使用负整数时会崩溃。初始显示功能有效,但它只是冻结。我试过一个签名的int数组无济于事。
我看了一遍,但找不到其他任何有这个问题的人。
int defaultArray[6] = { 12, -5, 21, -1, 15, 17 };
int numElements = 6;
int lastSwap;
int searchEnd = numElements - 1;
bool sorted = false;
while (!sorted)
{
for (int i = 0; i < searchEnd; ++i)
{
// If the number in position i is larger than the number in the
// position i + 1 then swap them
if (defaultArray[i] > defaultArray[i + 1]) {
int temp = defaultArray[i];
defaultArray[i] = defaultArray[i + 1];
defaultArray[i + 1] = temp;
lastSwap = i + 1;
}
}
// If the lastSwap is at position one we can conclude that the array is
// sorted so if lastSwap isn't 1 move searchEnd and continue
if (lastSwap != 1)
{
// Conclude that from lastSwap to the end of the array is sorted
// searchEnd begins one position to the left of lastSwap
searchEnd = lastSwap - 1;
}
else {
sorted = true;
}
答案 0 :(得分:1)
您正在尝试优化算法,减少searchEnd
,我认为存在问题。我建议你保持searchEnd
相同。要确定数组是否已排序,请将sorted
设置为true并启动while循环,并在发生交换时将其更改为false。例如:
while (!sorted) {
sorted = true;
for (int i = 0; i < searchEnd; ++i) {
if (defaultArray[i] > defaultArray[i + 1]) {
// swap
sorted = false;
}
}
}