Question

        var wRoot = new ctypes.unsigned_long();
        var wParent = new ctypes.unsigned_long();
        var wChild = new ctypes.unsigned_long.ptr();
        var nChildren = new ctypes.unsigned_int();

        var rez = XQueryTree(_disp, w, wRoot.address(), wParent.address(), wChild.address(), nChildren.address())
        if(rez != 0) { //can probably test this against `None` instead of `0`
            var nChildrenCasted = ctypes.cast(nChildren, ctypes.unsigned_int).value;
            for(var i=0; i<nChildrenCasted; i++) {
                searchForPidStartingAtWindow(wChild[i]);
            }
        } else {
            console.warn('this window has no children, rez:', rez);
        }

我成功地获得了nChildrenCasted它的94。

但是我无法访问wChild个元素，它应该是一个数组

问题在于：searchForPidStartingAtWindow(wChild[i]);

如何传递wChild[i]？

我试过了：

var wChildCasted = ctypes.cast(wChild, ctypes.unsigned_long).contents;
console.log('wChildCasted:', wChildCasted);

我很确定它沿着这些路线，但我无法弄清楚

完整代码，可以从便笺簿复制粘贴并运行：

https://gist.github.com/Noitidart/224f8999eb26ec52894f

Answer 1

您需要从原始指针类型转换为ArrayType指针：

var wChildCasted = ctypes.cast(wChild, ctypes.ArrayType(ctypes.unsigned_long, nChildrenCasted).ptr).contents;

X11 js-ctypes，XQueryTree访问wChild [i]

1 个答案: