Question

我是工作和正则表达的新手。我正在使用php。

对于以下字符串，我想提取报告编号。

Dear Patient! (patient name) Your Reports(report number) has arrived.

有人可以帮助我创建正则表达式。

谢谢

解决了：

$str ='Dear Patient! (P.JOHN) Your Reports (REPORTNO9) has arrived.';
$str = str_replace('(', '', $str);
$str = str_replace(')', '', $str);
preg_match('/Reports\s*(\w+)/', $str, $match);
echo $match[1]; //=> "REPORTNO9"

Answer 1

正则表达式

/Dear (\w+)! Your Reports(.*?)(?=has arrived)/

PHP使用

<?php
$subject = 'Dear Patient! Your Reports(report number) has arrived.';
if (preg_match('/Dear (\w+)! Your Reports(.*?)(?=has arrived)/', $subject, $regs)) {
    var_dump($regs);
}

<强>结果

array(3) {
  [0]=>
  string(42) "Dear Patient! Your Reports(report number) "
  [1]=>
  string(7) "Patient"
  [2]=>
  string(16) "(report number) "
}

<强>解释

"
Dear\             # Match the characters “Dear ” literally
(                 # Match the regular expression below and capture its match into backreference number 1
   \w                # Match a single character that is a “word character” (letters, digits, etc.)
      +                 # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
!\ Your\ Reports  # Match the characters “! Your Reports” literally
(                 # Match the regular expression below and capture its match into backreference number 2
   .                 # Match any single character that is not a line break character
      *?                # Between zero and unlimited times, as few times as possible, expanding as needed (lazy)
)
(?=               # Assert that the regex below can be matched, starting at this position (positive lookahead)
   has\ arrived      # Match the characters “has arrived” literally
)
"

Answer 2

您可以使用＆＃34; split（）＆＃34;提取这样的字符串的特定部分，所以你不必使用正则表达式：

<?php
    $my_string = ""; // Put there you string
    $array_my_string = array();

    $array_my_string = split('Reports', $my_string);

    $tempResult = array_my_string[1]; // Will contains "(report number) has arrived."

    $array_my_string = split(' has arrived', $tempResult);

    $finalResult = $array_my_result[0]; // Will contains "(report number)"
?>

使用正则表达式从字符串中提取数据

2 个答案: