如果条件不正常

Question

当我输入正确的电子邮件和错误的密码时，我看到“电子邮件不存在！” 为什么:(？

$emailnumrow = mysql_num_rows(mysql_query(" SELECT * FROM users WHERE email='$email' "));

if($emailnumrow['.$email.'] >= 1){
 } else {echo 'email do not exist!';}

Answer 1

mysql_num_rows返回int而不是array。它应该是

if($emailnumrow >= 1){
    ....
}else {
    echo 'email do not exist!';
}