Question

不确定我的编程在哪里出错。目标是加载文件并找到连续元音最多的单词。这段代码没有给我正确的单词。它给了我＆＃34; aalii＆＃34;什么时候应该给我＆＃34; cooeeing＆＃34;有人可以帮帮我吗？

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class manyVowels {

    public static void main(String[] args) {

        Scanner fileIn = null;
        try {
            //locate and open file
            fileIn = new Scanner(new FileInputStream("words.txt"));
        } catch (FileNotFoundException e) {
            //if the file cannot be found, the program prints the message and quits
            System.out.println("File not found. ");
            System.exit(0);
        }
        String word;
        if (fileIn.hasNext()) //if there is another word do as shown below
        {
        //seek consecutive vowels
        word = fileIn.next();
            for(int i=0;i <word.length();i++){
                if((word.charAt(i) == 'A') || 
                    (word.charAt(i) == 'E') ||
                    (word.charAt(i) == 'I') || 
                    (word.charAt(i) == 'O') ||
                    (word.charAt(i) == 'U') ||
                (word.charAt(i) == 'a') || 
                    (word.charAt(i) == 'e') ||
                    (word.charAt(i) == 'i') || 
                    (word.charAt(i) == 'o') ||
                    (word.charAt(i) == 'u')) {
            //prints the final word with the most consecutive vowels
            System.out.println("The word with the most consecutive vowels is: " + word);
            System.exit(0);
        }

        fileIn.close();
    }
}}}

更新：我到目前为止，但现在它说第34行在线程＆＃34;主要＆＃34;中有一个＆＃34;异常。显示java.lang.NullPointerException＆＃34;

＆＃13;

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class manyVowels {

  public static final String wordList = "words.txt";

  public static void main(String[] args) {
        Scanner fileIn = null;
        try {
            //locate and open file
            fileIn = new Scanner(new FileInputStream("words.txt"));
        } catch (FileNotFoundException e) {
            //if the file cannot be found, the program prints the message and quits
            System.out.println("File not found. ");
            System.exit(0);
        }
        String word = null;
        if (fileIn.hasNext()) //if there is another word continue
        {

            String finalWord = null; // defines the word with most consecutive vowels
            int maxVowels = 0;//sets initial value to 0
            while (fileIn.hasNext()) {
                // for each word in the file
                int vowels = 0;
                for (int i = 0; i < word.length() && i < word.length() - maxVowels + vowels; i++) {
                    // for each character in the word, and exit early if the word is not long enough to beat maxVowels
                    if (hasVowels(word.charAt(i))) {
                        // consonants reset this to 0
                        vowels++;
                    } else {
                        // reached the end of the word so check if the count is higher than maxVowels
                        if (vowels > maxVowels) {
                            maxVowels = vowels;
                            finalWord = word;
                        }
                        vowels = 0;
                    }
                }
                // comparing vowels to maxVowels
                if (vowels > maxVowels) {
                    maxVowels = vowels;
                    finalWord = word;
                }
            }

            //seek vowels
            word = fileIn.next();
            for (int i = 0; i < word.length(); i++) {
                if
                        ((word.charAt(i) == 'A')
                        || (word.charAt(i) == 'E')
                        || (word.charAt(i) == 'I')
                        || (word.charAt(i) == 'O')
                        || (word.charAt(i) == 'U')
                        || (word.charAt(i) == 'a')
                        || (word.charAt(i) == 'e')
                        || (word.charAt(i) == 'i')
                        || (word.charAt(i) == 'o')
                        || (word.charAt(i) == 'u')) {
                    //prints the final word with the most consecutive vowels
                    System.out.println("The word with the most consecutive vowels is: " + word);
                    System.exit(0);
                }

            }
        }
    }

    private static boolean hasVowels(char charAt) {
        throw new UnsupportedOperationException("Inserted by template."); //NetBeans generated method
    }
}

＆＃13;

Answer 1

尝试用简单的语言写出你的程序，你实际上没有检查有多少连续的元音。

Open file
If the file contains a word, continue
For each letter in the first word do:
    if the letter is a vowel,
        print "The word with the most consecutive vowels is: " + word
        exit the program

所以你实际上没有检查有多少个连续的元音，而是检查第一个单词中是否有元音。

尝试编写一些你想要分解的伪代码，就像我在你编写程序之前所做的一样

Answer 2

而不是

if（fileIn.hasNext（））使用而（fileIn.hasNext（））

如何打印连续元音最多的单词？

2 个答案: