MySQLi编写的声明＆amp; foreach循环

Question

我正在努力修改以下（有效）以使用预先准备好的声明：

echo "<div class=\"debug\">
            <h4>values \$_POSTed from *LINE-ITEMS TABLE* in input.php:</h4>
            <table>";

    foreach ($_POST['date'] as $i => $value) {
        $invNum     = $_POST['invNum'];
        $date           = $_POST['date'][$i];
        $hours      = $_POST['hours'][$i];
        $rate           = $_POST['rate'][$i];
        $dateTotal  = $_POST['dateTotal'][$i];

        echo "<tr>
                    <td>".$i."</td>
                    <td>".$date."</td>
                    <td>".$hours."</td>
                    <td>".$rate."</td>
                    <td>".$dateTotal."</td>
                </tr>";

            $query = "INSERT INTO Invoice_Line_Items SET
                INVOICE_NUMBER  = '$invNum',
                DATE                = '$date',
                HOURS               = '$hours',
                RATE                = '$rate',
                DATE_TOTAL      = '$dateTotal'

                ON DUPLICATE KEY UPDATE
                INVOICE_NUMBER  = VALUES(INVOICE_NUMBER),
                DATE                = VALUES(DATE),
                HOURS               = VALUES(HOURS),
                RATE                = VALUES(RATE),
                DATE_TOTAL      = VALUES(DATE_TOTAL)
                ";

        } // END foreach
echo "</table></div>";

我一直在尝试调整在此上面运行的（工作）预处理语句/查询在同一页面中，该页面将一行插入另一个表中。但是，第二个查询（进入不同的db表）从源表单中的行项表中插入多个（动态＃）行的数据。

我一直在攻击它好几个小时，但我无法理清如何使用line-items循环实现预处理语句。我认为这将是沿着这些方向，但这不是插入。

echo "<div class=\"debug\">
            <h4>values \$_POSTed from *LINE-ITEMS TABLE* in input.php:</h4>
            <table>";

// this is the line-items table in the form; don't I have to get these values before the query?
foreach ($_POST['date'] as $i => $value) {
    $invNum     = $_POST['invNum'];
    $date           = $_POST['date'][$i];
    $hours      = $_POST['hours'][$i];
    $rate           = $_POST['rate'][$i];
    $dateTotal  = $_POST['dateTotal'][$i];
    // confirm vars/values
    echo "<tr><td>".$i."</td><td>".$date."</td><td>".$hours."</td><td>".$rate."</td><td>".$dateTotal."</td></tr>";

    $stmt = $mysqli->stmt_init();
    $query = "INSERT INTO Invoice_Line_Items
        INVOICE_NUMBER  = '$invNum',
        DATE                = '$date',
        HOURS               = '$hours',
        RATE                = '$rate',
        DATE_TOTAL      = '$dateTotal'

        ON DUPLICATE KEY UPDATE
        INVOICE_NUMBER  = VALUES(INVOICE_NUMBER),
        DATE                = VALUES(DATE),
        HOURS               = VALUES(HOURS),
        RATE                = VALUES(RATE),
        DATE_TOTAL      = VALUES(DATE_TOTAL)
        ";

        if ($stmt->prepare($query)) {
            $stmt -> bind_param("ssddd", $invNum, $date, $hours, $rate, $dateTotal);
            $stmt -> execute();
            $stmt->close();
        } // if $stmt
} // END foreach

echo "</table></div>";

有人可以说清楚吗？非常感谢。

SVS

Answer 1

您不需要

$stmt = $mysqli->stmt_init();

您应该可以致电

$stmt = $mysqli->prepare($query);

另一个问题是你在>你的循环中设置了查询。你不应该这样做。将$stmt移到循环外部，只有在设置变量后才在execute内运行。最后，您需要添加?，以便MySQL知道参数

$query = "INSERT INTO Invoice_Line_Items
    INVOICE_NUMBER  = ?,
    DATE = ?,
    HOURS = ?,
    RATE  = ?,
    DATE_TOTAL = ?

    ON DUPLICATE KEY UPDATE
    INVOICE_NUMBER  = VALUES(INVOICE_NUMBER),
    DATE                = VALUES(DATE),
    HOURS               = VALUES(HOURS),
    RATE                = VALUES(RATE),
    DATE_TOTAL      = VALUES(DATE_TOTAL)
    ";
 $invNum = $date = $hours = $rate = $dateTotal = '';
 $stmt = $mysqli->prepare($query);
 $stmt->bind_param("ssddd", $invNum, $date, $hours, $rate, $dateTotal);

foreach ($_POST['date'] as $i => $value) {
    $invNum     = $_POST['invNum'];
    $date           = $_POST['date'][$i];
    $hours      = $_POST['hours'][$i];
    $rate           = $_POST['rate'][$i];
    $dateTotal  = $_POST['dateTotal'][$i];
    $stmt->execute();
}