Question

Hibernate抛出异常：

    org.hibernate.PropertyAccessException: 
could not get a field value by reflection getter of test.model.Part.part

部分实体类：

@Table(name = "part")
@Entity
public class Part implements Serializable {

    @Id @GeneratedValue
    @Column(name = "part")
    private int part;

    public int getPart() {
        return part;
    }

    public void setPart(int part) {
        this.part = part;
        }
@OneToMany(mappedBy = "part")
        private Collection<ProductPart> productPartsByPart;
        public Collection<ProductPart> getProductPartsByPart() {
            return productPartsByPart;
        }
    .....
  }

似乎实体类具有正确的注释，但Hibernate无法访问id表中Part和主键的属性。怎么解决？

它被称为：

ProductPart productPart  = (ProductPart) sessionFactory
                .getCurrentSession()
                .createCriteria(ProductPart.class)
                .add(Restrictions.eq("part", cPartId))
                .add(Restrictions.eq("product", productId)).uniqueResult();

更新

    Caused by: java.lang.IllegalArgumentException: 
Can not set int field Part.part   to java.lang.Integer

更新2： 我有product_part表，其中 fk 并在part表中引用了part。我必须使用@OneToMany(mappedBy = "part")吗？

@Entity
@Table (name = "part")
public class Part implements Serializable {

    @Id @GeneratedValue
    @Column(name = "part")
    @OneToMany(mappedBy = "part")
    private int  part;

UPDATE3

当我声明我只需要在Part表上执行搜索时，我不明白为什么Hibernate 会尝试访问 product_part表。它也没有必要访问其他表，因为我只需要product_part中的字段，该字段为 part 和 product （这两个都是外键）赋值。 ..

UPDATE4：

@Entity
@Table(name = "product_part")
public class ProductPart implements Serializable {

    @Id
    @GeneratedValue
    @Column(name = "id")
    private int id;


    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    @ManyToOne
    @JoinColumn(name = "product", referencedColumnName = "product", nullable = false)
    private Product product;

    public Product getProduct() {
        return product;
    }

    public void setProduct(Product product) {
        this.product = product;
    }


    @JoinColumn(name = "part", referencedColumnName = "part", nullable = false)
    @ManyToOne
    private Part part;

    public Part getPart() {
        return part;
    }

    public void setPart(Part partByPart) {
        this.part = partByPart;
    }
}

Answer 1

您的产品零件中如何引用您的零件？

应该是像

这样的东西

ProductPart{

@ManyToOne
private Part part;
}

猜是这样

将.add(Restrictions.eq("part", cPartId))更改为.add(Restrictions.eq("part.part", cPartId))

修改

ProductPart productPart = (ProductPart) sessionFactory .getCurrentSession() .createCriteria(ProductPart.class) .add(Restrictions.eq("part.part", cPartId)) .add(Restrictions.eq("product", productId)).uniqueResult();//here similarly access your Product's @Id //something like product.productId

Hibernate无法访问带注释属性的值

1 个答案: