Question

正在寻找从下面一行中删除[11:55:43] [Server thread/INFO]:的方法：

[11:55:43] [Server thread/INFO]: Justin has just earned the achievement [Time to Mine!]

尝试通过使用sed尝试这样做但没有运气，因为Justin可以根据获得成就的人更改为其他用户名。

有没有办法可以在用户名称之前删除[11:55:43] [Server thread/INFO]:而无需指定它？ IE浏览器。 sed from has，但保持在前面并删除任何事情？

Answer 1

使用sed：

sed 's/\[.*\] \[.*\]: //' file
Justin has just earned the achievement [Time to Mine!]

Answer 2

实现这一目的的sed命令是：

sed 's/^.*: //'

e.g。

echo '[11:55:43] [Server thread/INFO]: Justin has just earned the achievement [Time to Mine!]' |\
    sed 's/^.*: //'
Justin has just earned the achievement [Time to Mine!]

Answer 3

使用sed：

sed -e 's/^\[[^]]*\][^[]*\[[^]]*\]: //'

如果匹配[（某事）]（某事）[（某事）]:

，则会删除每行的开头

Answer 4

这应该可以解决问题：

sed 's/.*: \([^ ]* has .*\)/\1/' file

Answer 5

sed 's/^\( *\[[^]]*]\)\{2\}: //' YourFile

同时允许[...]
假设您的样本

]:

[...]

印刷线与结构不匹配

posix compliance（所以--posix与GNU sed）

Answer 6

A gawk。

源文件：

$ cat infile
[11:55:43] [Server thread/INFO]: Justin has just earned the achievement [Time to Mine!]
[11:58:43] [Server thread/INFO]: Martin has just earned the achievement [Time to Mine!]

代码：

$ gawk -F']: '  'BEGIN{OFS=""}{$1=""}1'  infile
Justin has just earned the achievement [Time to Mine!]
Martin has just earned the achievement [Time to Mine!]

如何从单词之前删除文本？

6 个答案: