我从页面资源中做了一个很好的Imageslider。现在,我尝试使用资源中提供的链接来超链接这些图像。这就是我到目前为止所做的:
TS:
lib.headerimage = COA_INT
lib.headerimage {
1 = COA
1 {
stdWrap.required = 1
stdWrap.outerWrap.cObject = TEXT
stdWrap.outerWrap.cObject.value = <li><img src=" | " /></li>
2 = IMG_RESOURCE
2 {
file {
import.data = levelmedia:-1, slide
import.listNum = 0
treatIdAsReference = 1
}
}
}
2 < .1
2.2.file.import.listNum = 1
3 < .1
3.2.file.import.listNum = 2
}
布局:
<div class="headerimage">
<ul>
<f:render section="headerimage" />
</ul>
</div>
此结果是预期的HTML输出
<ul>
<li>
<img />
</li>
</ul>
但我想要以下输出
<ul>
<li>
<a href="link_from_page_ressource">
<img />
</a>
</li>
</ul>
如何在图片周围获取这些链接?
提前致谢
更新
解决方案:
lib.headerimage = COA
lib.headerimage {
1 = FILES
1 {
references {
data = levelmedia:-1, slide
}
renderObj = COA
renderObj {
wrap = <li>|</li>
1 = IMAGE
1 {
file.import.data = file:current:publicUrl
altText.data = file:current:title
stdWrap.typolink.parameter.data = file:current:link
}
}
}
}
答案 0 :(得分:6)
您应该使用FILES
来处理此问题。使用类似的东西(未经测试!)
lib.headerimage = COA
lib.headerimage {
wrap = <ul>|</ul>
10 = FILES
10 {
references {
data = levelmedia:-1, slide
}
renderObj = COA
renderObj {
10 = IMAGE
10 {
file.import.data = file:current:publicUrl
altText.data = file:current:title
stdWrap.typolink.parameter.data = file:current:link
wrap = <li>|</li>
}
}
}
}
答案 1 :(得分:1)
你能试试吗?
lib.headerimage = COA
lib.headerimage {
wrap = <ul>|</ul>
1 = IMAGE
1 {
file {
import.data = levelmedia:-1, slide
import.listNum = 0
treatIdAsReference = 1
}
stdWrap.typolink.parameter.data = file:current:link
stdWrap.outerWrap = <ul>|</ul>
}
2 < .1
2.file.import.listNum = 1
3 < .1
3.file.import.listNum = 2
}
答案 2 :(得分:1)
lib.randomImage = COA_INT
lib.randomImage.10 = FILES
lib.randomImage.10.sorting = rand()
lib.randomImage.10 {
references {
table = pages
data = levelmedia:-1, slide
treatIdAsReference = 1
}
maxItems= 1
renderObj = COA
renderObj {
10 = IMAGE
10 {
file {
import {
data = file:current:publicUrl
}
}
}
}
stdWrap {
wrap = |
}
}
这个对我有用!