Question

我有两个用户名和密码的edittexts，我使用seterror方法在两者都为空时显示错误。问题是当第二个字段（密码字段）中弹出错误消息时，部分消息丢失。这个bug只存在于较旧的设备上。如何确保旧设备中不会发生错误。

我的代码：

public class SignInPage extends Activity {

    EditText txtusername,txtpassword;
    Button btnlogin;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.signinpage);
        txtusername=(EditText) findViewById(R.id.txtusername);
        txtpassword=(EditText) findViewById(R.id.txtpassword);
        btnlogin=(Button) findViewById(R.id.btnlogin);
        btnlogin.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                if(txtusername.getText().toString().trim().equals(""))
                {
                    txtusername.setError("Username is mandatory");
                    txtusername.requestFocus();
                }
                if(txtpassword.getText().toString().trim().equals(""))
                {
                    txtpassword.setError("Password is mandatory");
                    txtpassword.requestFocus();
                }
                else
                {
                    Toast.makeText(getApplicationContext(),"Checking with server",Toast.LENGTH_LONG).show();
                }
            }
        });
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
    }

}

Answer 1

试试这可能会对你有所帮助

fname = FirstName.getText().toString().trim();
if(fname.isEmpty()) //&& fname.matches("[a-zA-Z ]+"))
             {
                 FirstName.requestFocus();
                 FirstName.setError(Html.fromHtml("<font color='red'>Please enter the First name</font>")); 
             }
TextWatcher textWatcher = new TextWatcher() {

        @Override
        public void onTextChanged(CharSequence arg0, int arg1, int arg2, int arg3) 
        { }

        @Override
        public void beforeTextChanged(CharSequence arg0, int arg1, int arg2, int arg3) 
        { }

        @Override
        public void afterTextChanged(Editable arg0) 
        {
            if(arg0.toString().isEmpty()) 
            {
                return;
            }

            if (FirstName.getText() == arg0) {
                Validate(FirstName);
FirstName.addTextChangedListener(textWatcher);

public void Validate(EditText et) {     
    et.setError(null);
}

使用seterror方法验证android中的edittext

1 个答案: