Question

我想创建一个c ++程序，可以计算3年内售出的数量。

我想用2维数组和for循环（练习题的要求）

来做

但不知怎的，我无法得到我想要的结果。计算和存储之间存在一些误差。你能帮我辨认一下这个错误吗？

#include <iostream>
#include <string>
#include <array>
using namespace std;
int main(){
    int quantity[3][12];
    int sum[3];
    int *p;
    p=sum;
    int total;
    int year=0;
    string months[12]={
        "January",
        "February",
        "March",
        "April",
        "May",
        "June",
        "July",
        "August",
        "September",
        "Octorber",
        "November",
        "December"
    };
    for (int i=0; i<12; i++) {
        cout<<"Enter the quantity sold in "<<months[i]<<endl;
        cin>>quantity[year][i];
        if(i==11&&year<3){
            year++;
            i=-1;
        }
    }
    year=0;
    for (int i=0; i<12; i++) {
        sum[year]+=quantity[year][i];
        if (i==11&&year<3) {
            i=(-1);
            year++;
        }
    }
    year=0;
        for (int i=0; i<3; i++) {
            cout<<"the information for year "<<(i+1)<<" is " <<endl;
            for (int i1=0; i1<12; i1++) {
                cout<<quantity[year][i1]<<endl;
            }
            cout<<"the sum of the "<< (i+1)<< " year: "<<sum[year]<<endl;
            total+=sum[year];
        }
    cout<<"the total amount sold in three year is "<<total<<endl;

    return 0;
}

Answer 1

问题出在本节：

    year=0;
        for (int i=0; i<3; i++) {
            cout<<"the information for year "<<(i+1)<<" is " <<endl;
            for (int i1=0; i1<12; i1++) {
                cout<<quantity[year][i1]<<endl;
            }
            cout<<"the sum of the "<< (i+1)<< " year: "<<sum[year]<<endl;
            total+=sum[year];
        }
    cout<<"the total amount sold in three year is "<<total<<endl;

    return 0;
}

看起来你认为你正在迭代一年，而你实际上正在迭代i和i1。为什么不使用你使用的相同技巧而不是i1 for loop？

if (i==11&&year<3) {
    i=(-1);
    year++;
}

c ++ for循环和2维数组

1 个答案: