我正在为我正在重修的这门课做这个家庭作业，我遇到的问题是我过度思考解决方案。我必须创建一个程序，将四位数转换为单词。
（例如：1134变成“一三四”）
我有一个基本的代码，但它很笨重。我也只允许使用基本的if和switch语句，我们也必须使用switch语句。
我在想这个吗？我无法弄清楚如何使这段代码更短，我只想使用一个没有while循环的switch语句。它是否可能，或者它是否尽可能短。
这是我的代码。
import java.util.Scanner;
public class NumberToWords {
public static void main(String[] args) {
//Set up scanner.
Scanner kb = new Scanner(System.in);
//Ask for a 4 digit integer.
System.out.println("Enter a 4 digit number.");
//Store 4 digit number into a variable
int number = kb.nextInt();
//Seperate number into digits.
int digit4 = number%10;
number = number/10;
int digit3 = number%10;
number = number/10;
int digit2 = number%10;
number = number/10;
int digit1 = number%10;
number = number/10;
//Set up a switch statement to read through the number.
switch (digit1)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit2)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit3)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
switch (digit4)
{
case 1: System.out.print("One ");break;
case 2: System.out.print("Two "); break;
case 3: System.out.print("Three "); break;
case 4: System.out.print("Four "); break;
case 5: System.out.print("Five "); break;
case 6: System.out.print("Six "); break;
case 7: System.out.print("Seven "); break;
case 8: System.out.print("Eight "); break;
case 9: System.out.print("Nine "); break;
case 0: System.out.print("Zero "); break;
default: System.out.print(""); break;
}
}
}
答案 0 :(得分：2)
首先，编写一个将单个数字转换为单词的方法。像，
private static String digitToWord(char ch) {
switch(ch) {
case '0': return "Zero";
case '1': return "One";
case '2': return "Two";
case '3': return "Three";
case '4': return "Four";
case '5': return "Five";
case '6': return "Six";
case '7': return "Seven";
case '8': return "Eight";
case '9': return "Nine";
}
return "Unknown (" + ch + ")";
}
然后，您可以获得String的{{1}}值。并从int获取四个字符。像，
String或者，
int number = kb.nextInt();
String str = String.format("%04d", number);
StringBuilder sb = new StringBuilder();
sb.append(digitToWord(str.charAt(0)).append(' ');
sb.append(digitToWord(str.charAt(1)).append(' ');
sb.append(digitToWord(str.charAt(2)).append(' ');
sb.append(digitToWord(str.charAt(3));
System.out.println(sb.toString());
答案 1 :(得分：1)
这可能会有所帮助
public class NumbersInWords {
public static void main(String[] args) {
String number = "153";
int numLength = number.length();
System.out.println(numLength);
String numberToWord = "";
for (int j = 0; j < numLength; j++) {
switch (number.charAt(j)) {
case '1': {
numberToWord = numberToWord + "one";
break;
}
case '2': {
numberToWord = numberToWord + "two";
break;
}
case '3': {
numberToWord = numberToWord + "three";
break;
}
case '4': {
numberToWord = numberToWord + "four";
break;
}
case '5': {
numberToWord = numberToWord + "five";
break;
}
case '6': {
numberToWord = numberToWord + "six";
break;
}
case '7': {
numberToWord = numberToWord + "seven";
break;
}
case '8': {
numberToWord = numberToWord + "eight";
break;
}
case '9': {
numberToWord = numberToWord + "nine";
break;
}
default: {
numberToWord = numberToWord + "zero";
}
}
}
System.out.println(numberToWord);
}
}
答案 2 :(得分：0)
是的，您可以在for循环中执行该操作，执行4次。除法和mod在10处是一致的。像
For i = 0; i < 4; i++
Number/10%10
Condition to check number
Save number in array or print
答案 3 :(得分：0)
使用数字复制粘贴代码和名称应该是一个红色标记以使用循环（或更多的东西）。
private static final String[] DIGIT_NAMES = new String[] {"Zero ", "One ", "Two ",
"Three ", "Four ", "Five ", "Six ", "Seven ", "Eight ", "Nine "};
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int number = 0;
do {
// ask for a 4 digit integer
System.out.println("Enter a 4 digit number: ");
try {
number = input.nextInt();
} catch (InputMismatchException ignore) {
System.out.println("Recieved non integer input");
input.next(); // clear bad input
}
} while (number < 1000 || number > 9999);
String result = "";
while (number != 0) {
result = DIGIT_NAMES[number % 10] + result;
number = number / 10;
}
System.out.println(result);
input.close();
}