Question

如何使用LINQ创建和显示随机整数2-D数组？请帮帮我！我创建随机2-D数组，但不是LINQ。

Random rnd = new Random();

int[,] matrix = new int[rows, columns];
for (int i = 0; i < matrix.GetLength(0); i++)
    for (int j = 0; j < matrix.GetLength(1); j++)
        matrix[i, j] = rnd.Next(-100,100);
Console.WriteLine("Array:");
for (int i = 0; i < matrix.GetLength(0); i++)
{
    for (int j = 0; j < matrix.GetLength(1); j++)
        Console.Write("{0}\t", matrix[i, j]);
    Console.WriteLine();
}

Answer 1

使用linq创建一个10x10阵列：

   var r = new Random();
   var result = Enumerable.Range(0, 10).Select(x => 
                   Enumerable.Range(0, 10).Select(y => r.Next()).ToArray())
               .ToArray();

Answer 2

如果你真的想要过度复杂化：

    static void Main(string[] args)
    {
        int rows = 10;
        int columns = 10;
        int[,] matrix = new int[rows, columns];
        Random rnd = new Random();

        Enumerable.Range(0, rows)
            .ToList()
            .ForEach(row => Enumerable.Range(0, columns)
                .ToList()
                .ForEach(column => 
                    {
                        matrix[row, column] = rnd.Next(-100, 100);
                        Console.Write(column == columns ? Environment.NewLine + matrix[row, column].ToString() + "\t" : matrix[row, column].ToString() + "\t");
                    }));

        Console.ReadKey();
    }

LINQ c＃的随机2-D数组

2 个答案: