class Program
{
static void Main(string[] args)
{
//array of strings
string[] phrases = { "Buy it today", "You won't regret your purchase", "Satisfaction is guaranteed", "Purchase of a lifetime", "Such a great deal", "Limited time only" };
Random r = new Random();
string random = phrases[r.Next(0, 5)];
string random2 = phrases[r.Next(0, 5)];
string random3 = phrases[r.Next(0, 5)];
RanStrings(random, random2, random3);
}
private static void RanStrings(string random, string random2, string random3)
{
Console.WriteLine(random);
Console.WriteLine(random2);
Console.WriteLine(random3);
}
}
答案 0 :(得分:0)
你的问题不是很清楚,但根据我的理解,你需要一种检查方法的方法,如:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace FormLetter
{
class Program
{
static void Main(string[] args)
{
string random="";
string random2 ="";
string random3 ="";
do{
//array of strings
string[] phrases = { "Buy it today", "You won't regret your purchase", "Satisfaction is guaranteed", "Purchase of a lifetime", "Such a great deal", "Limited time only" };
Random r = new Random();
random = phrases[r.Next(0, 5)];
random2 = phrases[r.Next(0, 5)];
random3 = phrases[r.Next(0, 5)];
}while(compareStrings(random,random2, random3))
RanStrings(random, random2, random3);
}
private static void RanStrings(string random, string random2, string random3)
{
Console.WriteLine(random);
Console.WriteLine(random2);
Console.WriteLine(random3);
}
private static bool compareStrings(string random, string random2, string random3)
{
//put here your comparison code
if (there is equality between 2 strings passed in argument)
return true;
else return false;
}
}
}
答案 1 :(得分:0)
听起来你想" shuffle"字符串而不是随意挑选一个(基本上随机选择而不替换)。如果是这种情况,只需使用带有随机数的OrderBy
:
Random r = new Random();
string[] phrases = { "Buy it today", "You won't regret your purchase", "Satisfaction is guaranteed", "Purchase of a lifetime", "Such a great deal", "Limited time only" };
phrases = phrases.OrderBy(s => r.Next()).ToArray();
// now just take the "first" 3
RanStrings(phrases[0], phrases[1], phrases[2]);