我想在发生异常时重定向到包含错误代码的注册页面。我怎么能在烧瓶中做到这一点?如何使用错误代码重定向到同一页面?
@app.route('/signup', methods=['GET','POST'])
def signup():
error = None
if request.method == 'POST':
try:
... my code ...
except Exception, e:
error = "hey this is error"
... i want to redirect to signup with error ...
... i get only some stacktrace page due to debug ...
return redirect(url_for('login'))
return render_template('signup.html', error=error)
答案 0 :(得分:2)
你需要放置try / except依赖的return语句来处理它。问题在于,无论try /中发生了什么,除非它进入if语句,它总是会进入登录页面。你需要相应地分解你的退货声明。
@app.route('/signup', methods=['GET','POST'])
def signup():
error = None
if request.method == 'POST':
try:
... my code ...
return redirect(url_for('login'))
except Exception, e:
error = "hey this is error"
... i want to redirect to signup with error ...
return render_template('signup.html', error=error)
return render_template('signup.html', error=error)