Question

我需要查询SQLCE表并将结果集转换为XML。数据库的列：

line_id     int
ref_no      nvarchar(20)
. . .
new_item    int

...与所需的XML进行1：1映射：

<INV>
<line_id>1</line_id>
<ref_no>valerie</ref_no>
. . .
<new_item>-1</new_item>
</INV>

我可以生成这样的XML（伪代码）：

int lineId;
String refNum;
. . .
String strXML;
StringBuilder sbXML;
. . . // loop through result set
lineId = resultSet[0];
refNum = resultSet[1];
. . .
strXML = String.Format("<INV><line_id>{0}</line_id><ref_no>{1}</ref_no>. . .<new_item>{2}</new_item></INV>", lineId, refNum, . . .newItem);
sbXML.Add(strXML);

......但这看起来很笨拙。有更优雅的解决方案吗？

更新

我使用了ctacke提供的链接中的第一个例子，现在我有：

. . .
string xmlOutput = String.Empty;
. . .
XmlDocument doc = new XmlDocument();
XmlDeclaration dec = doc.CreateXmlDeclaration("1.0", null, null);
doc.AppendChild(dec);
XmlElement root = doc.CreateElement("Command");
doc.AppendChild(root);

try
{
    while (dtr.Read())
    {
        // outer INV
        XmlElement invRec = doc.CreateElement("INV");

        // Line ID
        lineId = dtr["line_id"].ToString(); // Wiggly uses dtr.GetString(1); would then have to use GetX()...
        XmlElement _lineId = doc.CreateElement("line_id");
        _lineId.InnerText = lineId;
        invRec.AppendChild(_lineId);

        // Ref Num
        refNum = dtr["ref_no"].ToString();
        XmlElement _refNum = doc.CreateElement("ref_no");
        _refNum.InnerText = refNum;
        invRec.AppendChild(_refNum);
        . . .
        root.AppendChild(invRec);
    }
}
finally
{
    //doc.AppendChild(root); <= Should this be here instead of above?
    xmlOutput = doc.OuterXml;
}
. . .

更新2

或者，对于可以在没有任何设置的情况下提升和丢弃/填充的测试代码：

private void button29_Click(object sender, EventArgs e)
{
    string xmlOutput = String.Empty;
    String lineId;
    String refNum;
    String upcCode;
    String desc;
    String dept;
    String vendorId;
    String upcPackSize;
    String Id;
    String packSize;
    String unitCost;
    String unitList;
    String unitQty;
    String newItem;

    XmlDocument doc = new XmlDocument();
    XmlDeclaration dec = doc.CreateXmlDeclaration("1.0", null, null);
    doc.AppendChild(dec);
    XmlElement root = doc.CreateElement("Command");
    doc.AppendChild(root);    

    try
    {
            // outer INV
            XmlElement invRec = doc.CreateElement("INV");

            // Line ID
            lineId = "some line id";
            XmlElement _lineId = doc.CreateElement("line_id");
            _lineId.InnerText = lineId;
            invRec.AppendChild(_lineId);

            // Ref Num
            refNum = "some ref num";
            XmlElement _refNum = doc.CreateElement("ref_no");
            _refNum.InnerText = refNum;
            invRec.AppendChild(_refNum);

            // UPC Code
            upcCode = "some upc code";
            XmlElement _upc_code = doc.CreateElement("upc_code");
            _upc_code.InnerText = upcCode;
            invRec.AppendChild(_upc_code);

            // Description
            desc = "some desc";
            XmlElement _description = doc.CreateElement("description");
            _description.InnerText = desc;
            invRec.AppendChild(_description);

            // Department
            dept = "some dept";
            XmlElement _department = doc.CreateElement("department");
            _department.InnerText = dept;
            invRec.AppendChild(_department);

            // Vendor Id
            vendorId = "some vendor id";
            XmlElement _vendor_id = doc.CreateElement("vendor_id");
            _vendor_id.InnerText = vendorId;
            invRec.AppendChild(_vendor_id);

            // UPC Pack Size
            upcPackSize = "some upc pack size";
            XmlElement _upc_pack_size = doc.CreateElement("upc_pack_size");
            _upc_pack_size.InnerText = upcPackSize;
            invRec.AppendChild(_upc_pack_size);

            // Id
            Id = "some id";
            XmlElement _id = doc.CreateElement("id");
            _id.InnerText = Id;
            invRec.AppendChild(_id);

            // Pack Size
            packSize = "some pack size";
            XmlElement _pack_size = doc.CreateElement("pack_size");
            _pack_size.InnerText = packSize;
            invRec.AppendChild(_pack_size);

            // Unit Cost
            unitCost = "some unit cost";
            XmlElement _unit_cost = doc.CreateElement("unit_cost");
            _unit_cost.InnerText = unitCost;
            invRec.AppendChild(_unit_cost);

            // Unit List
            unitList = "some unit list";
            XmlElement _unit_list = doc.CreateElement("unit_list");
            _unit_list.InnerText = unitList;
            invRec.AppendChild(_unit_list);

            // Unit Qty
            unitQty = "some unit qty";
            XmlElement _unit_qty = doc.CreateElement("unit_qty");
            _unit_qty.InnerText = unitQty;
            invRec.AppendChild(_unit_qty);

            // New Item
            newItem = "some New item";
            XmlElement _new_item = doc.CreateElement("new_item");
            _new_item.InnerText = newItem;
            invRec.AppendChild(_new_item);

            root.AppendChild(invRec);
    }
    finally
    {
        xmlOutput = doc.OuterXml;
        MessageBox.Show(xmlOutput); 
    }    
}

Answer 1

你肯定不想要使用字符串格式。既然您已经降级到.NET 1.0（从未有过.NETCF 1.1），那么您将使用XmlDocument类作为起点，并使用它来创建随后添加到文档中的节点和属性。与LINQ的XDocument相比，它非常难看，但它是你拥有的工具。

快速搜索turned up this example，这是一本很好的入门书。

有没有将SQLCE查询结果转换为XML的标准方法？

更新

更新2

1 个答案: