Question

我正在尝试让PHP向我展示一些timeago功能。我正在循环遍历Mysql表中的结果，其中有一个名为“aplicationdate”的列名称，数据库中的格式为“Ymd”..但它只是显示了一些负数大数字，如-16328 ..这是我的timeago filev任何帮助将不胜感激：

<? php

function timeAgo($time_ago) {
    $cur_time = date('Y-m-d');
    $time_elapsed = $cur_time - $time_ago;

    $days = round($time_elapsed / 86400);
    $weeks = round($time_elapsed / 604800);
    $months = round($time_elapsed / 2600640);
    $years = round($time_elapsed / 31207680);

    //Days
    if ($days <= 7) {
        if ($days == 1) {
            echo "yesterday";
        } else {
            echo "$days days ago";
        }
    }
    //Weeks
    else if ($weeks <= 4.3) {
        if ($weeks == 1) {
            echo "a week ago";
        } else {
            echo "$weeks weeks ago";
        }
    }
    //Months
    else if ($months <= 12) {
        if ($months == 1) {
            echo "a month ago";
        } else {
            echo "$months months ago";
        }
    }
    //Years
    else {
        if ($years == 1) {
            echo "one year ago";
        } else {
            echo "$years years ago";
        }
    }
}

?>

这是如何在另一个名为profile.php的文件中实现的，timeago文件包含在这个文件中

 <? php

 $mysqli = new mysqli("localhost", "root", "", "cx");

 /* check connection */
 if ($mysqli - > connect_errno) {
     printf("Connect failed: %s\n", $mysqli - > connect_error);
     exit();
 }


 $idced_history = $_GET['idced'];

 $query = "SELECT * FROM applications WHERE idced='$idced_history'";

 if ($result = $mysqli - > query($query)) {

     while ($row = $result - > fetch_assoc()) {

         $curenttime = $row["applicationdate"];
         $time_ago = strtotime($curenttime);

         echo "<br><b>Applied On:</b> ".$row["applicationdate"]."  ".timeAgo($time_ago)."  <br>";


     }

     $result - > free();
 }

 $mysqli - > close();
?>

Answer 1

$cur_time是一个字符串，而不是数字。看起来您需要在使用它之前将其转换为Unix时间戳。因此，请使用time()代替date()：

 $cur_time  = time();

（假设$time_ago也是Unix时间戳）

无法在PHP循环中实现此timeAgo功能

1 个答案: