Question

我需要帮助才能找到文本中的字符串，该文本以@开头，直到preg_match在php中的下一个直接空格

Ex：我想从这一行获取@string作为单独的。在这个例子中，我需要提取＆＃34; @ string＆＃34;从这条线上独自一人。

任何机构都可以帮我找到解决办法。

提前致谢！

Answer 1

PHP和Python在搜索方面并不相同。如果你已经在捕获中使用了strip_tags这样的函数，那么像这样的东西可能比其他一个答案中提供的Python示例更好，因为我们也可以使用look-around assertions。

<?php
$string = <<<EOT
I want to get @string from this line as separate.
In this example, I need to extract "@string" alone from this line.

@maybe the username is at the front.

Or it could be at the end @whynot, right!

dog@cat.com would be an e-mail address and should not match.        

EOT;

echo $string."<br>";

preg_match_all('~(?<=[\s])@[^\s.,!?]+~',$string,$matches);
print_r($matches);
?>

输出结果

Array
(
    [0] => Array
        (
            [0] => @string
            [1] => @maybe
            [2] => @whynot
        )

)

更新

如果您直接从HTML流本身拉出来，那么查看Twitter HTML，它的格式如下：

<s>@</s><b>UserName</b>

因此，为了匹配html流中的用户名，您将匹配以下内容：

<?php

$string = <<<EOT
<s>@</s><b>Nancy</b> what are you on about?

I want to get <s>@</s><b>string</b> from this line as separate. In this example, I need to extract "@string" alone from this line.

<s>@</s><b>maybe</b> the username is at the front.

Or it could be at the end <s>@</s><b>WhyNot</b>, right!

dog@cat.com would be an e-mail address and should not match.        

EOT;

$matchpattern = '~(<s>(@)</s><b\>([^<]+)</b>)~';
preg_match_all($matchpattern,$string,$matches);


$users = array();
foreach ($matches[0] as $username){
    $cleanUsername = strip_tags($username);
    $users[]=$cleanUsername;
}

print_r($users);

<强>输出

Array
(
    [0] => @Nancy
    [1] => @string
    [2] => @maybe
    [3] => @WhyNot
)

Answer 2

只需简单地做：

preg_match('/@\S+/', $string, $matches);

结果位于$matches[0]

preg_match使用php获取@符号之后和下一个空格之前的文本

2 个答案:

更新