Question

我在ActionBar中使用Dialog Builder使用SingleChoiceItems。我需要在退出应用程序后保存所选项目，以便在再次访问应用程序时恢复已保存的设置。

先决条件 - ＆gt;我看到很多共享首选项和onRestoreInstance和OnSaveInstance的例子，但我很困惑。下面的代码解释了我的所作所为。

- 对话框生成器----

我在 - ＆gt;中保存了所选选项的当前状态selectPosition ..然后将selectedPosition保存在全局变量isChecked中并将其设置为SelectSingleChoice参数

private void displaySortDialog() {

    final CharSequence[] sort_options = {"Z-A", "A-Z", "Size"};


    AlertDialog.Builder builder = new AlertDialog.Builder(this);

    builder.setTitle(getString(R.string.sort_apps));


        builder.setSingleChoiceItems(sort_options, isChecked, new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog, int selected_sort) {
                Toast.makeText(getApplicationContext(), sort_options[selected_sort], Toast.LENGTH_SHORT).show();

            }
        });

    builder.setPositiveButton("OK", new DialogInterface.OnClickListener() {
           public void onClick(DialogInterface dialog, int id) {

               int selectedPosition = ((AlertDialog)dialog).getListView().getCheckedItemPosition(); 
               Toast.makeText(getApplicationContext(), "Choose:"+selectedPosition, Toast.LENGTH_SHORT).show();


               if(selectedPosition == 0){
                  Collections.shuffle(applist);
                  Toast.makeText(getApplicationContext(), "Shuffles the present order list", Toast.LENGTH_SHORT).show();
               }
               else if(selectedPosition == 1){
                   Collections.sort(applist, new ApplicationInfo.DisplayNameComparator(packageManager));
                   Toast.makeText(getApplicationContext(), "Sorts Alphabetically", Toast.LENGTH_SHORT).show();
               }
               else if(selectedPosition == 2){
                   Collections.reverse(applist); 
                   Toast.makeText(getApplicationContext(), "Reverses the present order selected", Toast.LENGTH_SHORT).show();
               }

               isChecked = selectedPosition;

           }
       });
    builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
           public void onClick(DialogInterface dialog, int id) {
                dialog.cancel();
           }
    });


    builder.create().show();
}

使用以下代码。当我长按home按钮的主页按钮从thr应用程序选择的设置似乎没问题，他们被选中并保存为我祝酒消息，以确保他们被选中似乎onSaveInstanceState正在工作我猜coz OnSaveInstance Toast msg显示..但是当我尝试恢复通过OnRestoreInsatanceMethod保存的设置时，它无法正常工作..退出应用程序后，设置将恢复为默认值

public void onRestoreInstanceState(Bundle savedInstanceState) {
if(savedInstanceState != null){ 
    isChecked = savedInstanceState.getInt("SELECTED_SORT_ITEM");
    Toast.makeText(getApplicationContext(), "RESTORED: "+isChecked, Toast.LENGTH_SHORT).show();
}

}

public void onSaveInstanceState(Bundle savedInstanceState) {
//outState.putInt(SELECTED_SORT_ITEM, getActionBar().getSelectedNavigationIndex());
super.onSaveInstanceState(savedInstanceState);
savedInstanceState.putInt(SELECTED_SORT_ITEM, isChecked);
Toast.makeText(getApplicationContext(), SELECTED_SORT_ITEM+isChecked, Toast.LENGTH_SHORT).show();

}

OnSaveInstanceRestore 的Toast会在我从应用程序按回原点时显示，或者长按主页按钮再次选择应用程序。但退出应用程序后，我无法恢复所选设置..

如果你能用这些方法或其他方法帮助我，那将是值得注意的。

由于

在退出后访问Appl时，恢复已保存的操作栏选项设置状态

0 个答案: