Question

它不返回标题。那么我可以在查询中更改什么呢？

$query = (new Query())->select('title')->from('topics')->where(['id' => [1, 2, 3]]);
return $query->title;

Answer 1

您的查询形成类似 -

SELECT title FROM topics WHERE id IN (1,2,3);

所以你将获得数组数组。您还需要执行查询。

尝试 -

$query = (new \yii\db\Query())->select(['title'])->from('topics')->where(['id' => [1, 2, 3]]);
$command = $query->createCommand();
$data = $command->queryAll();
$titles = '';
foreach($data as $row) {
    $titles .= $row['title'] . ', ';
}
return rtrim($titles, ', ');

每个记录都会得到title，逗号分隔。

Answer 2

试试这段代码：

$users=[1,2,3];
User::find()->where('id IN('.$users.')');

Answer 3

 [
   'attribute' => 'topic_id',
   'format' => 'raw',
   'value' => function($data){
    $query = (new Query())->select(['title'])->from('topics')->where(['id' => [1, 2, 3]]);
      $command = $query->createCommand();
      $data= $command->queryAll();
      foreach($data as $row)
        return  $data['title'];
      }
 ],

m把这段代码放在这里但是错误产生了这个。

未定义的索引：标题

标题可用于主题表。

使用选择yii2中的查询位置

3 个答案: