Question

我正在处理的这个脚本从数据库中检索电子邮件，如果它们符合任何条件，将发送一封电子邮件，并更新数据库，说明已发送电子邮件。

我可以让脚本执行此操作，但我无法通过迭代遍历数组中的所有电子邮件。它将运行一个电子邮件的脚本，然后它将出错：在非对象上调用成员函数execute（）。所以我从中理解的是，当foreach循环遍历另一封电子邮件时，该变量内部没有任何内容可供查询插入数据库。

如果我通过刷新页面再次运行脚本，它将插入在上次调用期间没有发送的电子邮件，但它会为阵列中的下一封电子邮件提供相同的错误。

所以我的问题是：如何让我的脚本迭代遍历数组中的所有电子邮件，而不会出错？

date_default_timezone_set('America/Los_Angeles');
$today = date('m/d/Y h:i:s a');

$time = time();

require('addrow_info.php');
//connect to database
$mysqli = new mysqli('localhost', $username, $password, $database);
if(!$mysqli){
die('Not connected :' . mysqli_error($mysqli));
}

$query = $mysqli->query("SELECT * FROM abandoned WHERE orderStatus IS NULL ORDER BY time DESC");
if(!$query){
die('Invalid query :' . mysqli_error($mysqli));
}

while($email = mysqli_fetch_array($query)){

$abandoned[] = array(
    'email' => $email['email'],
    'time' => $email['time'],
    'status' => $email['orderStatus'],
    'attempts' => $email['attempts']
    );
}

$mysqli->close();

//open new connection
$mysqli = new mysqli('localhost',$username,$password,$database);
if(!$mysqli){
 die('Not connected : ' . mysqli_error($mysqli));
}

foreach($abandoned as $viewAbandoned){

$timeAbandoned = strtotime($viewAbandoned['time']);

if($timeAbandoned < strtotime('-1 hour') && $viewAbandoned['attempts'] == '0'){

    echo "Order by " . $viewAbandoned['email'] . " was abandoned more than 1 hour ago<br/>";

    //send email to remind them of items in their cart
    $to = 'josan.iracheta@gmail.com';
    $subject = 'new abandoned email';
    $message = $viewAbandoned['email'];

    $sendmail = mail($to,$subject,$message);

        if(!$sendmail){
            echo "Mail not sent!";
            }
            else{
            echo "Mail sent!";

            //update database with email attempt

             $update = $mysqli->query("UPDATE abandoned SET attempts = '1' WHERE email = '".$viewAbandoned['email']."' ");
             $updateResult = $update->execute();

            }//end if Mail was sent, database was updated with attempt

    }//end if abandoned cart is more than 1 hour old

    //if email has been sent once, send after 6 hours
    elseif($timeAbandoned < strtotime('-6 hours') && $viewAbandoned['attempts'] == '1'){

    //send email to remind them of items in their cart
    $to = 'josan.iracheta@gmail.com';
    $subject = 'new abandoned email';
    $message = 'Second notice ' . $viewAbandoned['email'];

    $sendmail = mail($to,$subject,$message);

        if(!$sendmail){
            echo "Mail not sent!";
            }
            //if mail is sent
            else{
            echo "Mail sent!";

            //update database with email attempt

             $update = $mysqli->query("UPDATE abandoned SET attempts = '2' WHERE email = '".$viewAbandoned['email']."' ");
             $updateResult = $update->execute();

            }//end if Mail was sent
            //database was updated with attempt

    }

    //send email after 24 hours
    elseif($timeAbandoned < strtotime('-24 hours') && $viewAbandoned['attempts'] == '2'){

    //send email to remind them of items in their cart
    $to = 'josan.iracheta@gmail.com';
    $subject = 'new abandoned email';
    $message = 'third notice' . $viewAbandoned['email'];

    $sendmail = mail($to,$subject,$message);

        if(!$sendmail){
            echo "Mail not sent!";
            }
            else{
            echo "Mail sent!";

            //update database with email attempt

             $update = $mysqli->query("UPDATE abandoned SET attempts = '3' WHERE email = '".$viewAbandoned['email']."' ");
             $updateResult = $update->execute();

            }//end if Mail was sent
            //database was updated with attempt

    }

    //send email after one week
    elseif($timeAbandoned < strtotime('-168 hours') && $viewAbandoned['attempts'] == '3'){

    //send email to remind them of items in their cart
    $to = 'josan.iracheta@gmail.com';
    $subject = 'new abandoned email';
    $message = 'It has been one week already' . $viewAbandoned['email'];

    $sendmail = mail($to,$subject,$message);

        if(!$sendmail){
            echo "Mail not sent!";
            }
            else{
            echo "Mail sent!";

            //update database with email attempt

             $update = $mysqli->query("UPDATE abandoned SET attempts = '4' WHERE email = '".$viewAbandoned['email']."' ");
             $updateResult = $update->execute();

            }//end if Mail was sent
            //database was updated with attempt

    }

}//end foreach loop

Answer 1

我认为您的计划在点击$updateResult = $update->execute();行时会中断，因为$mysqli->query()对于成功的 DML 查询返回true。 Documentation Here

我相信如果你用执行调用删除行，它应该解决你的问题。

如果您想保留执行行，则需要将query()更改为prepare()

用于运行mysqli查询的条件语句

1 个答案: