Question

我的mysql数据库中有这个JSON编码的代码：

{"Suggestion":{"Title":"Casinos","Text":"maybe it will be good if its there casinos "},"ID":6,"VoteNo":[],"Status":"Voting","Player":{"SteamID":"STEAM_0:1:36988062","Name":"Pepi"},"Approved":{"Name":"Nido Johnson","Is":true,"SteamID":"STEAM_0:0:47457253"},"VoteYes":{"1":"STEAM_0:0:56939043","2":"STEAM_0:0:55948188","3":"STEAM_0:1:25856984","4":"STEAM_0:1:40894071"}}

我想查询并解码它以在我的网站上回复它。

Answer 1

你必须使用php＆＃34; json_decode（）＆＃34;用于解码json编码数据的函数。基本上json_decode（）函数将JSON数据转换为PHP数组。

语法：json_decode（data，dataTypeBoolean，depth，options）

数据： - 要在PHP中解码的json数据。

dataTypeBoolean（可选）： - 布尔值，如果设置为＆＃34; true＆＃34;，则使函数返回PHP关联数组，如果省略此参数，则返回PHP stdClass对象或设置为＆＃34; false＆＃34;。这两种数据类型都可以像数组一样访问，并使用基于数组的PHP循环进行解析。

深度： - 可选的递归限制。使用整数作为此参数的值。

选项： - 可选的JSON_BIGINT_AS_STRING参数。

现在来到您的代码

    $json_string = '{"Suggestion":{"Title":"Casinos","Text":"maybe it will be good if its there casinos "},"ID":6,"VoteNo":[],"Status":"Voting","Player":{"SteamID":"STEAM_0:1:36988062","Name":"Pepi"},"Approved":{"Name":"Nido Johnson","Is":true,"SteamID":"STEAM_0:0:47457253"},"VoteYes":{"1":"STEAM_0:0:56939043","2":"STEAM_0:0:55948188","3":"STEAM_0:1:25856984","4":"STEAM_0:1:40894071"}}';

将有效的json数据分配给单个“＃”中的变量$ json_string（＆＃39;＆＃39;）as json字符串已经有双重报价。

// here i am decoding a json string by using a php 'json_decode' function, as mentioned above & passing a true parameter to get a PHP associative array otherwise it will bydefault return a PHP std class objecy array.

    / just can check here your encoded array data.
// echo '<pre>';
// print_r($json_decoded_data);

// loop to extract data from an array
foreach ($json_decoded_data as $key => $value) {
    echo "$key <br/>";
    foreach($value as $k=>$data)
    {
        echo "$k | $data <br/>";
    }

}

查询和解码json形式的mysql数据库

1 个答案: