Question

出于文档目的，我想展示可用于描述球体上的位置的各种球面坐标系（即位置可以描述为xyz坐标或翻转方位角，方位角 - 超高或超高方位角等）。

我没有在.net上找到清晰的插图，特别是对于非常规约定，我想使用matlab创建简单的插图，如下面的一个（翻转方位角系统），其中，imao，是直截了当地理解：

enter image description here

无论如何我想知道如何创建弯曲的箭头以显示角度方向（上图中的phi / theta箭头）。使用quiver3绘制直向量是可以的。我尝试阅读stream3，但没有明白使用情况。我想要一些简单的东西：

function [h] = CreateCurvedArrow(startXYZ, endXYZ)
%[
     % Draw curved-line in the plane defined by 
     % vectors 'Origin->StartXYZ' and 'Origin->EndXYZ'
     % going from 'StartXYZ' to 'EndXYZ'
%]

我希望有一些简单的方法可以做到这一点，我会使用线段来处理。

Answer 1

只是为了乐趣：

Curved Arrows

算法缓慢地将Center->StartPoint向量旋转到Center->EndPoint轴周围的Normal向量，并使用中间点绘制弯曲箭头。当然可以进一步改进实施：

function [] = TestCurvedArrow()
%[
    hold on
    CreateCurvedArrow3(0.3*[1 0 0], 0.3*[0 1 0]);
    CreateCurvedArrow3(0.2*[0 1 0], 0.2*[0 0 1]);
    CreateStraightArrow([0 0 0], [1 0 0], 'r');
    CreateStraightArrow([0 0 0], [0 1 0], 'g');
    CreateStraightArrow([0 0 0], [0 0 1], 'b');
    hold off
    daspect([1 1 1]);
%]
end

%% --- Creates a curved arrow
% from: Starting position - (x,y,z) upplet
% to: Final position - (x,y,z) upplet
% center: Center of arc - (x,y,z) upplet => by default the origin
% count: The number of segment to draw the arrow => by default 15
function [h] = CreateCurvedArrow3(from, to, center, count)
%[        
    % Inputs
    if (nargin < 4), count = 15; end
    if (nargin < 3), center = [0 0 0]; end
    center = center(:); from = from(:); to = to(:);

    % Start, stop and normal vectors    
    start = from - center; rstart = norm(start);
    stop = to - center; rstop = norm(stop);
    angle = atan2(norm(cross(start,stop)), dot(start,stop));
    normal = cross(start, stop); normal = normal / norm(normal);

    % Compute intermediate points by rotating 'start' vector
    % toward 'end' vector around 'normal' axis
    % See: http://inside.mines.edu/fs_home/gmurray/ArbitraryAxisRotation/
    phiAngles = linspace(0, angle, count);
    r = linspace(rstart, rstop, count) / rstart;
    intermediates = zeros(3, count);
    a = center(1); b = center(2); c = center(3);
    u = normal(1); v = normal(2); w = normal(3); 
    x = from(1); y = from(2); z = from(3);
    for ki = 1:count,
        phi = phiAngles(ki);
        cosp = cos(phi); sinp = sin(phi);
        T = [(u^2+(v^2+w^2)*cosp)  (u*v*(1-cosp)-w*sinp)  (u*w*(1-cosp)+v*sinp) ((a*(v^2+w^2)-u*(b*v+c*w))*(1-cosp)+(b*w-c*v)*sinp); ...
             (u*v*(1-cosp)+w*sinp) (v^2+(u^2+w^2)*cosp)   (v*w*(1-cosp)-u*sinp) ((b*(u^2+w^2)-v*(a*u+c*w))*(1-cosp)+(c*u-a*w)*sinp); ...   
             (u*w*(1-cosp)-v*sinp) (v*w*(1-cosp)+u*sinp)  (w^2+(u^2+v^2)*cosp)  ((c*(u^2+v^2)-w*(a*u+b*v))*(1-cosp)+(a*v-b*u)*sinp); ...
                      0                    0                      0                                1                               ];
        intermediate = T * [x;y;z;r(ki)];
        intermediates(:,ki) = intermediate(1:3);
    end

    % Draw the curved line
    % Can be improved of course with hggroup etc...
    X = intermediates(1,:);
    Y = intermediates(2,:);
    Z = intermediates(3,:);    
    tf = ishold;
    if (~tf), hold on; end
    h = line(X,Y,Z);       
    quiver3(X(end-1), Y(end-1), Z(end-1), X(end)-X(end-1), Y(end)-Y(end-1), Z(end)-Z(end-1),1);    
    if (~tf), hold off; end
%]
end

%% --- Creates normal arrow
% from: Starting position - (x,y,z) upplet
% to: Final position - (x,y,z) upplet
% lineSpec: Line specifications 
function [h] = CreateStraightArrow(from, to, lineSpec)
%[
    h = quiver3(from(1), from(2), from(3), to(1)-from(1), to(2)-from(2), to(3)-from(3), lineSpec);
%]
end

在matlab中的弯曲的箭头

1 个答案: