我正在尝试使用EF6更新记录。首先找到记录,如果存在,则更新它。 这是我的代码: -
var book = new Model.Book
{
BookNumber = _book.BookNumber,
BookName = _book.BookName,
BookTitle = _book.BookTitle,
};
using (var db = new MyContextDB())
{
var result = db.Books.SingleOrDefault(b => b.BookNumber == bookNumber);
if (result != null)
{
try
{
db.Books.Attach(book);
db.Entry(book).State = EntityState.Modified;
db.SaveChanges();
}
catch (Exception ex)
{
throw;
}
}
}
每次我尝试使用上面的代码更新记录时,我收到此错误: -
{System.Data.Entity.Infrastructure.DbUpdateConcurrencyException:Store 更新,插入或删除语句会影响意外的数量 行(0)。自实体以来,实体可能已被修改或删除 装了。刷新ObjectStateManager entrie
答案 0 :(得分:289)
您正在尝试更新记录(对我来说意味着"更改现有记录的值并将其保存回来")。因此,您需要检索对象,进行更改并保存。
using (var db = new MyContextDB())
{
var result = db.Books.SingleOrDefault(b => b.BookNumber == bookNumber);
if (result != null)
{
result.SomeValue = "Some new value";
db.SaveChanges();
}
}
答案 1 :(得分:126)
我一直在审查实体框架的源代码,如果您知道Key属性,在其他情况下需要检查AddOrUpdate实现,我找到了实际更新实体的方法:
public void Update<T>(T item) where T: Entity
{
// assume Entity base class have an Id property for all items
var entity = _collection.Find(item.Id);
if (entity == null)
{
return;
}
_context.Entry(entity).CurrentValues.SetValues(item);
}
希望这有帮助!
答案 2 :(得分:43)
您可以使用AddOrUpdate
方法:
db.Books.AddOrUpdate(book); //requires using System.Data.Entity.Migrations;
db.SaveChanges();
答案 3 :(得分:15)
所以你有一个更新的实体,你想用最少量的代码在数据库中更新它......
并发总是很棘手,但我假设你只是希望你的更新获胜。这是我为同一个案例做的事情,并修改名称来模仿你的类。换句话说,只需将add
更改为public static void SaveBook(Model.Book myBook)
{
using (var ctx = new BookDBContext())
{
ctx.Books.Add(myBook);
ctx.Entry(myBook).State = System.Data.Entity.EntityState.Modified;
ctx.SaveChanges();
}
}
,它就适用于我:
$today_start = date('Y-m-d').' 9:30:00';
$today_end = date('Y-m-d').' 18:30:00';
答案 4 :(得分:9)
此代码是测试的结果,该测试仅更新一组列而不先使查询返回记录。它首先使用Entity Framework 7代码。
// This function receives an object type that can be a view model or an anonymous
// object with the properties you want to change.
// This is part of a repository for a Contacts object.
public int Update(object entity)
{
var entityProperties = entity.GetType().GetProperties();
Contacts con = ToType(entity, typeof(Contacts)) as Contacts;
if (con != null)
{
_context.Entry(con).State = EntityState.Modified;
_context.Contacts.Attach(con);
foreach (var ep in entityProperties)
{
// If the property is named Id, don't add it in the update.
// It can be refactored to look in the annotations for a key
// or any part named Id.
if(ep.Name != "Id")
_context.Entry(con).Property(ep.Name).IsModified = true;
}
}
return _context.SaveChanges();
}
public static object ToType<T>(object obj, T type)
{
// Create an instance of T type object
object tmp = Activator.CreateInstance(Type.GetType(type.ToString()));
// Loop through the properties of the object you want to convert
foreach (PropertyInfo pi in obj.GetType().GetProperties())
{
try
{
// Get the value of the property and try to assign it to the property of T type object
tmp.GetType().GetProperty(pi.Name).SetValue(tmp, pi.GetValue(obj, null), null);
}
catch (Exception ex)
{
// Logging.Log.Error(ex);
}
}
// Return the T type object:
return tmp;
}
以下是完整的代码:
public interface IContactRepository
{
IEnumerable<Contacts> GetAllContats();
IEnumerable<Contacts> GetAllContactsWithAddress();
int Update(object c);
}
public class ContactRepository : IContactRepository
{
private ContactContext _context;
public ContactRepository(ContactContext context)
{
_context = context;
}
public IEnumerable<Contacts> GetAllContats()
{
return _context.Contacts.OrderBy(c => c.FirstName).ToList();
}
public IEnumerable<Contacts> GetAllContactsWithAddress()
{
return _context.Contacts
.Include(c => c.Address)
.OrderBy(c => c.FirstName).ToList();
}
//TODO Change properties to lambda expression
public int Update(object entity)
{
var entityProperties = entity.GetType().GetProperties();
Contacts con = ToType(entity, typeof(Contacts)) as Contacts;
if (con != null)
{
_context.Entry(con).State = EntityState.Modified;
_context.Contacts.Attach(con);
foreach (var ep in entityProperties)
{
if(ep.Name != "Id")
_context.Entry(con).Property(ep.Name).IsModified = true;
}
}
return _context.SaveChanges();
}
public static object ToType<T>(object obj, T type)
{
// Create an instance of T type object
object tmp = Activator.CreateInstance(Type.GetType(type.ToString()));
// Loop through the properties of the object you want to convert
foreach (PropertyInfo pi in obj.GetType().GetProperties())
{
try
{
// Get the value of the property and try to assign it to the property of T type object
tmp.GetType().GetProperty(pi.Name).SetValue(tmp, pi.GetValue(obj, null), null);
}
catch (Exception ex)
{
// Logging.Log.Error(ex);
}
}
// Return the T type object
return tmp;
}
}
public class Contacts
{
public int Id { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public string Email { get; set; }
public string Company { get; set; }
public string Title { get; set; }
public Addresses Address { get; set; }
}
public class Addresses
{
[Key]
public int Id { get; set; }
public string AddressType { get; set; }
public string StreetAddress { get; set; }
public string City { get; set; }
public State State { get; set; }
public string PostalCode { get; set; }
}
public class ContactContext : DbContext
{
public DbSet<Addresses> Address { get; set; }
public DbSet<Contacts> Contacts { get; set; }
public DbSet<State> States { get; set; }
protected override void OnConfiguring(DbContextOptionsBuilder optionsBuilder)
{
var connString = "Server=YourServer;Database=ContactsDb;Trusted_Connection=True;MultipleActiveResultSets=true;";
optionsBuilder.UseSqlServer(connString);
base.OnConfiguring(optionsBuilder);
}
}
答案 5 :(得分:6)
你应该使用。如果要更新对象中的所有字段,请使用Entry()方法。 另请注意,您无法更改字段ID(键),因此在编辑时首先将Id设置为某些ID。
using(var context = new ...())
{
var EditedObj = context
.Obj
.Where(x => x. ....)
.First();
NewObj.Id = EditedObj.Id; //This is important when we first create an object (NewObj), in which the default Id = 0. We can not change an existing key.
context.Entry(EditedObj).CurrentValues.SetValues(NewObj);
context.SaveChanges();
}
答案 6 :(得分:5)
以下是此问题的最佳解决方案:在视图中添加所有ID(密钥)。考虑将多个表命名为(第一,第二和第三)
@Html.HiddenFor(model=>model.FirstID)
@Html.HiddenFor(model=>model.SecondID)
@Html.HiddenFor(model=>model.Second.SecondID)
@Html.HiddenFor(model=>model.Second.ThirdID)
@Html.HiddenFor(model=>model.Second.Third.ThirdID)
在C#代码中,
[HttpPost]
public ActionResult Edit(First first)
{
if (ModelState.Isvalid)
{
if (first.FirstID > 0)
{
datacontext.Entry(first).State = EntityState.Modified;
datacontext.Entry(first.Second).State = EntityState.Modified;
datacontext.Entry(first.Second.Third).State = EntityState.Modified;
}
else
{
datacontext.First.Add(first);
}
datacontext.SaveChanges();
Return RedirectToAction("Index");
}
return View(first);
}
答案 7 :(得分:4)
using(var myDb = new MyDbEntities())
{
user user = new user();
user.username = "me";
user.email = "me@me.com";
myDb.Users.Add(user);
myDb.users.Attach(user);
myDb.Entry(user).State = EntityState.Modified;//this is for modiying/update existing entry
myDb.SaveChanges();
}
答案 8 :(得分:3)
您应该删除db.Books.Attach(book);
答案 9 :(得分:2)
Attach
设置实体将其跟踪状态设置为Unchanged
。要更新现有实体,只需将跟踪状态设置为Modified
。根据{{3}}:
如果您知道数据库中已经存在一个实体,但是可能已对其进行了更改,则可以告诉上下文附加该实体并将其状态设置为“已修改”。例如:
var existingBlog = new Blog { BlogId = 1, Name = "ADO.NET Blog" }; using (var context = new BloggingContext()) { context.Entry(existingBlog).State = EntityState.Modified; // Do some more work... context.SaveChanges(); }
答案 10 :(得分:2)
我找到了一种很好的方法。
var Update = context.UpdateTables.Find(id);
Update.Title = title;
// Mark as Changed
context.Entry(Update).State = System.Data.Entity.EntityState.Modified;
context.SaveChanges();
答案 11 :(得分:1)
这是我的后RIA实体更新方法(针对Ef6时间框架):
public static void UpdateSegment(ISegment data)
{
if (data == null) throw new ArgumentNullException("The expected Segment data is not here.");
var context = GetContext();
var originalData = context.Segments.SingleOrDefault(i => i.SegmentId == data.SegmentId);
if (originalData == null) throw new NullReferenceException("The expected original Segment data is not here.");
FrameworkTypeUtility.SetProperties(data, originalData);
context.SaveChanges();
}
请注意FrameworkTypeUtility.SetProperties()
是我在NuGet上的AutoMapper之前编写的一个很小的实用函数:
public static void SetProperties<TIn, TOut>(TIn input, TOut output, ICollection<string> includedProperties)
where TIn : class
where TOut : class
{
if ((input == null) || (output == null)) return;
Type inType = input.GetType();
Type outType = output.GetType();
foreach (PropertyInfo info in inType.GetProperties())
{
PropertyInfo outfo = ((info != null) && info.CanRead)
? outType.GetProperty(info.Name, info.PropertyType)
: null;
if (outfo != null && outfo.CanWrite
&& (outfo.PropertyType.Equals(info.PropertyType)))
{
if ((includedProperties != null) && includedProperties.Contains(info.Name))
outfo.SetValue(output, info.GetValue(input, null), null);
else if (includedProperties == null)
outfo.SetValue(output, info.GetValue(input, null), null);
}
}
}
答案 12 :(得分:1)
.net核心
context.Customer.Add(customer);
context.Entry(customer).State = Microsoft.EntityFrameworkCore.EntityState.Modified;
context.SaveChanges();
答案 13 :(得分:1)
如果是用于Entity Framework 6.2.0。
如果您有特定的DbSet
且需要更新或创建的项目:
var name = getNameFromService();
var current = _dbContext.Names.Find(name.BusinessSystemId, name.NameNo);
if (current == null)
{
_dbContext.Names.Add(name);
}
else
{
_dbContext.Entry(current).CurrentValues.SetValues(name);
}
_dbContext.SaveChanges();
但是,它也可以用于具有单个主键或复合主键的通用DbSet
。
var allNames = NameApiService.GetAllNames();
GenericAddOrUpdate(allNames, "BusinessSystemId", "NameNo");
public virtual void GenericAddOrUpdate<T>(IEnumerable<T> values, params string[] keyValues) where T : class
{
foreach (var value in values)
{
try
{
var keyList = new List<object>();
//Get key values from T entity based on keyValues property
foreach (var keyValue in keyValues)
{
var propertyInfo = value.GetType().GetProperty(keyValue);
var propertyValue = propertyInfo.GetValue(value);
keyList.Add(propertyValue);
}
GenericAddOrUpdateDbSet(keyList, value);
//Only use this when debugging to catch save exceptions
//_dbContext.SaveChanges();
}
catch
{
throw;
}
}
_dbContext.SaveChanges();
}
public virtual void GenericAddOrUpdateDbSet<T>(List<object> keyList, T value) where T : class
{
//Get a DbSet of T type
var someDbSet = Set(typeof(T));
//Check if any value exists with the key values
var current = someDbSet.Find(keyList.ToArray());
if (current == null)
{
someDbSet.Add(value);
}
else
{
Entry(current).CurrentValues.SetValues(value);
}
}
答案 14 :(得分:1)
试一试......
的UpdateModel(书);
var book = new Model.Book
{
BookNumber = _book.BookNumber,
BookName = _book.BookName,
BookTitle = _book.BookTitle,
};
using (var db = new MyContextDB())
{
var result = db.Books.SingleOrDefault(b => b.BookNumber == bookNumber);
if (result != null)
{
try
{
UpdateModel(book);
db.Books.Attach(book);
db.Entry(book).State = EntityState.Modified;
db.SaveChanges();
}
catch (Exception ex)
{
throw;
}
}
}
答案 15 :(得分:1)
如Renat所说,删除:db.Books.Attach(book);
此外,将结果查询更改为使用“AsNoTracking”,因为此查询会丢弃实体框架的模型状态。它认为“结果”是现在要跟踪的书,你不希望这样。
var result = db.Books.AsNoTracking().SingleOrDefault(b => b.BookNumber == bookNumber);
答案 16 :(得分:0)
我知道它已经被回答好几次了,但是我喜欢下面的方法。我希望它能对某人有所帮助。
//attach object (search for row)
TableName tn = _context.TableNames.Attach(new TableName { PK_COLUMN = YOUR_VALUE});
// set new value
tn.COLUMN_NAME_TO_UPDATE = NEW_COLUMN_VALUE;
// set column as modified
_context.Entry<TableName>(tn).Property(tnp => tnp.COLUMN_NAME_TO_UPDATE).IsModified = true;
// save change
_context.SaveChanges();
答案 17 :(得分:0)
尝试使用Attach()然后使用SaveChanges()组合更新记录时遇到相同的问题,但是我使用的是SQLite DB及其EF提供程序(相同的代码在SQLServer DB中可以正常工作)。
我发现,当您的数据库列在SQLite中具有GUID(或UniqueIdentity)并且您的模型为nvarchar时,SQLIte EF默认将其视为Binary(即,byte [])。因此,当SQLite EF提供程序尝试将GUID转换为模型(在我的情况下为字符串)时,它将失败,因为它将转换为byte []。解决方法是通过定义“ BinaryGUID = false;”来告诉SQLite EF将GUID视为TEXT(因此转换为字符串,而不是byte [])。在连接字符串(或元数据,如果您首先使用数据库)中,如下所示:
<connectionStrings>
<add name="Entities" connectionString="metadata=res://savetyping...=System.Data.SQLite.EF6;provider connection string="data source=C:\...\db.sqlite3;Version=3;BinaryGUID=false;App=EntityFramework"" providerName="System.Data.EntityClient" />
</connectionStrings>
链接到对我有用的解决方案: How does the SQLite Entity Framework 6 provider handle Guids?
答案 18 :(得分:0)
与该特定示例无关,但是在尝试使用EF和DateTime字段作为并发检查字段时遇到了一个挑战。似乎EF并发代码不支持元数据(edmx)中的精度设置,即类型=“ DateTime” Precision“ 3”。 数据库datetime字段将在该字段中存储毫秒部分(即2020-10-18 15:49:02.123)。即使您将Entity的原始值设置为包含毫秒成分的DateTime,SQL EF也会生成以下内容:
;
如您所见,@ 2是一个不带毫秒成分的STRING表示形式。这将导致您的更新失败。
因此,如果要使用DateTime字段作为并发键,则在检索记录时必须从数据库字段中删除毫秒/滴答,并且仅使用/剥离类似的DateTime来传递/更新该字段。 / p>
UPDATE [dbo].[People]
SET [dateUpdated] = @0
WHERE (([PeopleID] = @1) AND ([dateUpdated] = @2))
-- @0: '10/19/2020 1:07:00 AM' (Type = DateTime2)
-- @1: '3182' (Type = Int32)
-- @2: '10/19/2020 1:06:10 AM' (Type = DateTime2)
当用新值更新字段时,也要减去毫秒
//strip milliseconds due to EF concurrency handling
PeopleModel p = db.people.Where(x => x.PeopleID = id);
if (p.dateUpdated.Millisecond > 0)
{
DateTime d = new DateTime(p.dateUpdated.Ticks / 10000000 * 10000000);
object[] b = {p.PeopleID, d};
int upd = db.Database.ExecuteSqlCommand("Update People set dateUpdated=@p1 where peopleId=@p0", b);
if (upd == 1)
p.dateUpdated = d;
else
return InternalServerError(new Exception("Unable to update dateUpdated"));
}
return Ok(p);