Question

我使用PHP curl登录网站，我的代码如下：

<?php  
$Luser = "";
$Lpass = "";

if(isset($_POST['username']) && isset($_POST['password']))
{
    $Luser = $_POST['username'];
    $Lpass = $_POST['password'];
    $L_info="http://registration.zwinky.com/registration/loginAjax.jhtmlusername=".$Luser."&password=".$Lpass;
    $zwinky_login_file = file_get_contents($L_info, true);
    if (substr($zwinky_login_file, 12, 1) == "u"){ $message = "Blank username!"; }
    if (substr($zwinky_login_file, 12, 1) == "p"){ $message = "Blank password!"; }
    if (substr($zwinky_login_file, 12, 1) == "w"){ $message = "Wrong user/pass combination!"; }
    if (substr($zwinky_login_file, 12, 1) == "s"){
    $ch = curl_init();

    curl_setopt($ch, CURLOPT_URL , $L_info);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_COOKIEFILE, "sessions/".$Luser);
    curl_setopt($ch, CURLOPT_COOKIEJAR, "sessions/".$Luser);
    $response = curl_exec($ch);
    curl_close($ch);

    $_SESSION['username'] = $Luser;
    $_SESSION['password'] = $Lpass;

    header('Location: http://idane.me/start.html');
    }
    echo($message);
}
?>

但我得到一个错误：

警告：无法修改标头信息 - 已经发送的标头（/customers/2/9/0/idane.me/httpd.www/login.php:49上的输出）/ customers / 2/9/0第73行的/idane.me/httpd.www/login.php

第73行：

header('Location: http://idane.me/start.html');

有什么不对吗？

Answer 1

第49行怎么样？

你应该在标题之后添加exit（）：

header('Location: http://idane.me/start.html');
exit();

卷曲登录，无法修改标题信息

1 个答案: