$variable = "test_company_insurance_llc_chennai_limited_w-8tyu.pdf";
我需要在$变量上面显示
Test Company Insurance LLC Chennai Limited W-8TYU.pdf
为此我已经完成了:
$variable = str_replace("_"," ","test_company_insurance_llc_chennai_limited_w-8tyu.pdf");
$test = explode(" ", $variable);
$countof = count($test);
for ($x=0; $x<$countof; $x++) {
if($test[$x] == 'w-8tyu' || $test[$x] == 'llc') {
$test[$x] = strtoupper($test[$x]);
//todo
}
}
我陷入了待办事项。
我将使用strtoupper将特定单词更改为大写。
稍后,我应该如何合并数组?
任何帮助都会感激...
答案 0 :(得分:3)
$str_in = "test_company_insurance_llc_chennai_limited_w-8tyu.pdf";
$lst_in = explode("_", $str_in);
$lst_out = array();
foreach ($lst_in as $val) {
switch($val) {
case "llc" : $lst_out[] = strtoupper($val);
break;
case "w-8tyu.pdf" : $lst_temp = explode('.', $val);
$lst_out[] = strtoupper($lst_temp[0]) . "." . $lst_temp[1];
break;
default : $lst_out[] = ucfirst($val);
}
}
$str_out = implode(' ', $lst_out);
echo $str_out;
答案 1 :(得分:1)
不是非常优雅,但可能稍微灵活一些。
$v = str_replace("_"," ","test_company_insurance_llc_chennai_limited_w-8tyu.pdf");
$acronyms = array('llc', 'w-8tyu');
$ignores = array('pdf');
$v = preg_replace_callback('/(?:[^\._\s]+)/', function ($match) use ($acronyms, $ignores) {
if (in_array($match[0], $ignores)) {
return $match[0];
}
return in_array($match[0], $acronyms) ? strtoupper($match[0]) : ucfirst($match[0]);
}, $v);
echo $v;
如果将扩展名与初始值分开,则可以删除忽略。
答案 2 :(得分:1)
请参阅下面的代码。我已将代码的输出打印为您预期的输出。所以跑吧回复我......
$variable = str_replace("_"," ","test_company_insurance_llc_chennai_limited_w-8tyu.pdf");
$test = explode(" ", $variable);
$countof = count($test);
for ($x=0; $x<$countof; $x++) {
if($test[$x] == 'llc') {
$test[$x] = strtoupper($test[$x]);
//todo
}elseif($test[$x] == 'w-8tyu.pdf'){
$file=basename($test[$x],'pdf');
$info = new SplFileInfo($test[$x]);
$test[$x] = strtoupper($file).$info->getExtension();
}
else{
$test[$x]=ucfirst($test[$x]);
}
}
echo '<pre>';
print_r($test);
echo '</pre>';
echo $output = implode(" ", $test);