Question

我从这样的API中获取字符串

  New version of WhatsApp Messenger is
  now available.
  JANUARY 12, 2013
  Your upgrade will bring improvements, larger
  group chats and new features such as
  Profile Photos!

有没有办法从上面的字符串中获取段落？

我使用了NSArray *paragraphs = [result componentsSeparatedByString:@"\n"];

根据我的要求，它应该有3个字符串

 paragraphs=   {
          "New version of WhatsApp Messenger is now available."
          "JANUARY 12, 2013"
          "Your upgrade will bring improvements, larger  group chats and new features such as Profile Photos!"

    }

但它的回归

paragraphs= {
      "New version of WhatsApp Messenger is"
      "now available."
      "JANUARY 12, 2013"
      "Your upgrade will bring improvements, larger"
      "group chats and new features such as"
      "Profile Photos!"
 }

Answer 1

你可以试试这个：

    NSArray* newLinestring = [result componentsSeparatedByCharactersInSet:[NSCharacterSet newlineCharacterSet]];

    NSMutableArray *newLinesArray = [NSMutableArray array];

   [result enumerateSubstringsInRange:NSMakeRange(0, result.length) options:NSStringEnumerationByParagraphs usingBlock:^(NSString *substring, NSRangesubstringRange, NSRange enclosingRange, BOOL *stop) {
  // ADD TO AN ARRAY HERE THE SUBSTRINGS
 }];

Answer 2

据我所知，输出是正确的，因为有5个换行符。输入不是你想要的。你的意见应该是：

New version of WhatsApp Messenger is now available.
JANUARY 12, 2013
Your upgrade will bring improvements, larger group chats and new features such as Profile Photos!

Answer 3

这是你的问题的黑客

1检查所有换行符。

2删除特定范围内的换行符。

3.done

1.  int count = 0;
    for (unsigned int i=0; i < [result length]; ++i) {
        if ([result characterAtIndex:i] == '\n') {
            NSLog(@"index %i",i);
            ++count;

        }
    }

2.  

    NSRange first = {36, 1};
    NSRange fourth= {113,1};
    NSRange fifth={150,1};
    NSString *stringWithSpaces;

    stringWithSpaces = [result stringByReplacingCharactersInRange:first withString:@" "];
    result=stringWithSpaces;
    stringWithSpaces = [result stringByReplacingCharactersInRange:fourth withString:@" "];
    result=stringWithSpaces;
    stringWithSpaces = [result stringByReplacingCharactersInRange:fifth withString:@" "];
    result=stringWithSpaces;

     NSArray *paragraphs = [result componentsSeparatedByString:@"\n"];
     NSLog(@"Paragraph=%@",paragraphs);

完成。

快乐编码

如何在iOS中以段落顺序获取NSString中的所有段落？

3 个答案: