Question

使用MVC结构我在TExt区域输入日期时出错在那种形式YYYY-MM-DD Ex：2014-09-17

它插入Mysql LIke这个0000-00-00

这是视图

   <html>
    <head>


    </head>
    <body>

                    <div class="register">
                <form action="InterventionController.php" method="POST"> 
                    <h1> Ajouter Une Date Pour L'intervention: </h1>
                    <input required="required" name="Date" class="input-group-addon" type="text" placeholder="Date Sous Forme :  yy-mm-dd ">


                    <input required="required" class="btn-primary btn-lg" type="submit" name="submit" value="Ajouter L'intervention">


                </form>

            </div>



    </body>


</html>

这是控制器

     <?php


if($_POST){

        if(isset($_POST['submit']) AND $_POST['submit'] == "Ajouter L'intervention" ){

      $data['Date']  =      $_POST['Date'];



       try {
           include 'models\AddInterventionModel.php';
            new AddInterventionModel($data);
           } catch (Exception $exc) {

               echo $exc->getMessage();
           }
        header("location:index.php?page=Demande_Inter");


    }



                    }
 else {
                        include 'Login.php';
 }




?>

这就是模块

<?php


class AddInterventionModel {



   private $Date;

   private $cnx; 

   function __construct($data) {

        if(is_array($data)){

            $this->setData($data);
           }
           else 
           {
               throw new Exception("Error Data Should Be An Array");

           }


           // Connect To Database
           $this->connectToDb();

           //Insert User Data 

           $this->AddInterventionModelF();

   }

   private function setData($data)
   {
       $this->Date      = $data['$Date'];



   }

   private function connectToDb() {
       include 'models/Database.php';
       $vars = "include/vars.php";
       $this->cnx = new Database($vars);

   }

   function AddInterventionModelF ()

   {
       $query = "INSERT INTO `intervention` (`ID_I`, `DATE_I`) VALUES('','$this->Date')";

       $sql = mysql_query($query);

       if($sql){
           echo 'Added Sussecfully';


       }
       else
       {

           throw new Exception("Error : not Added");
       }

   }

   function close(){

       $this->cnx->close();
   }

   }

Answer 1

首先，您将input＆＃34; Mname＆＃34;命名为，但您在控制器中呼叫$_POST['date']（因此您必须更改＆＃39; Mname＆＃39; in＆＃39;日期＆＃39;

其次，在模块中，您要验证日期是否为数组，但日期应为字符串。

最后，考虑使用此

$dateString = $_POST['date'];
if (!empty($dateString)) {
    $date = new \DateTime($dateString);
    $date->setTime(0, 0, 0);
}

然后在mysql查询中：

$query = "INSERT INTO `intervention` (`ID_I`, `DATE_I`) VALUES('','".$date->format('Y-m-d H:i')."')";

使用PHP的Mysql中的Insering日期出错：000-00-00

1 个答案: