如何创建异步任务，以便我可以使用不同的参数

Question

public class sendMesgTask extends AsyncTask<String, Void, Void> {

        String msg = "";

        @Override
        protected void onPreExecute() {
            super.onPreExecute();

        }

        @Override
        protected Void doInBackground(String... params) {
            try {
                String result = sendMsg(params[0]);
                msg = getResult(result);
            } catch (IOException e) {
                e.printStackTrace();
            } catch (JSONException e) {
                e.printStackTrace();
            }

            return null;
        }

        @Override
        protected void onPostExecute(Void result) {
            if (msg.equals("1")) {

            }
        }

        public String sendMsg(String message) throws IOException, JSONException {

            try {

                String sendmsgurl = "http://api.lociiapp.com/api/message/sendmessage?member_id="
                        + 452
                        + "&to_id="
                        + 452
                        + "&message="
                        + message
                        + "&Notificationtype="
                        + "3"
                        + "&notificationId="
                        + (int) (Math.random() * 100000000)
                        + "&notify_status="
                        + "false";
                Log.e("Valueeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee", sendmsgurl);

                System.out.println("Valueeeeeeeeeeeeeeeeeee" + sendmsgurl);
                URL url = new URL(sendmsgurl);
                URLConnection urlcon = url.openConnection();
                jsonResp = convertToString(urlcon.getInputStream());

            } catch (Exception e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            return jsonResp;
        }

        public String convertToString(InputStream is) {
            if (is != null) {
                Writer writer = new StringWriter();
                char[] buffer = new char[1024];
                try {
                    Reader reader = new BufferedReader(new InputStreamReader(
                            is, "UTF-8"));
                    int n;
                    while ((n = reader.read(buffer)) != -1) {
                        writer.write(buffer, 0, n);
                    }
                } catch (UnsupportedEncodingException e) {
                    // TODO: handle exception
                } catch (IOException e) {

                } finally {
                    try {
                        is.close();
                    } catch (IOException e) {

                    }
                }
                return writer.toString();
            } else {
                return "";
            }
        }

        private String getResult(String response) {

            String test = "";
            try {
                JSONObject json = (JSONObject) new JSONTokener(response)
                        .nextValue();
                test = json.getString("responseCode");
            } catch (JSONException e) {

            }
            return test;
        }

这是用于发送消息的类asynk任务我正在调用此asynk任务，就像这个新的sendMesgTask（）。执行（＆＃34; Rjected＆＃34;）;

我想像这样调用asynk任务：

new sendMesgTask().execute(452,452,Rejected,3,(int) (Math.random() * 100000000),false);  

请帮助我如何上课，以便我可以这样打电话

Answer 1

最好使用asynctask的构造函数，如下所示：

public class sendMesgTask extends AsyncTask<String, Void, Void> {

        String msg = "";
        int i;
        String j;

        public sendMesgTask(int i, String j){

            this.i = i;
            this.j = j;

        }
        @Override
        protected void onPreExecute() {
            super.onPreExecute();

        }

        @Override
        protected Void doInBackground(String... params) {
            try {
                String result = sendMsg(params[0]);
                msg = getResult(result);
            } catch (IOException e) {
                e.printStackTrace();
            } catch (JSONException e) {
                e.printStackTrace();
            }

            return null;
        }

现在，您可以在整个asynctask类中使用i和j变量。

并打电话：

new sendMesgTask(5,"test").execute();

Answer 2

为什么不使用像这样的构造函数方法

public class sendMesgTask extends AsyncTask<String, Void, Void> {


int num1;
int num2;
String accept_reject;
int num3; 
int randum_number;
boolean bool;


public sendMesgTask(int num1, int num2, String accept_reject, int num3, int randum_number, boolean bool){

this.num1=num1;
this.num2= num2;
this.accept_reject = accept_reject;
this.num3 = num3;
this.randum_number=randum_number;
this.bool=bool;
}

.
.
//Your rest of code remains same
.
.
.



}

像这样打电话

new sendMesgTask(452,452,Rejected,3,(int) (Math.random() * 100000000),false).execute();

编辑：1

new sendMesgTask(452,452,"Rejected",3,(int) (Math.random() * 100000000),false).execute();

好的，有你的问题

现在在你的doInBackground方法调用中就像这样

String result = sendMsg(sendeid,recciveid,msg,type,status);

而不是

String result = sendMsg(params[0]);

Answer 3

 public class sendMesgTask extends AsyncTask<Object, Void, String> {

    String msg = "";

    @Override
    protected void onPreExecute() {
        super.onPreExecute();

    }

    @Override
    protected Void doInBackground(Object... params) {
        try {
            String result = sendMsg(params[0]);
            msg = getResult(result);
        } catch (IOException e) {
            e.printStackTrace();
        } catch (JSONException e) {
            e.printStackTrace();
        }

        return null;
    }

    @Override
    protected void onPostExecute(Void result) {
        if (msg.equals("1")) {

        }
    }

    public String sendMsg(String message) throws IOException, JSONException {

        try {

            String sendmsgurl = "http://api.lociiapp.com/api/message/sendmessage?member_id="
                    + 452
                    + "&to_id="
                    + 452
                    + "&message="
                    + message
                    + "&Notificationtype="
                    + "3"
                    + "&notificationId="
                    + (int) (Math.random() * 100000000)
                    + "&notify_status="
                    + "false";
            Log.e("Valueeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee", sendmsgurl);

            System.out.println("Valueeeeeeeeeeeeeeeeeee" + sendmsgurl);
            URL url = new URL(sendmsgurl);
            URLConnection urlcon = url.openConnection();
            jsonResp = convertToString(urlcon.getInputStream());

        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        return jsonResp;
    }

    public String convertToString(InputStream is) {
        if (is != null) {
            Writer writer = new StringWriter();
            char[] buffer = new char[1024];
            try {
                Reader reader = new BufferedReader(new InputStreamReader(
                        is, "UTF-8"));
                int n;
                while ((n = reader.read(buffer)) != -1) {
                    writer.write(buffer, 0, n);
                }
            } catch (UnsupportedEncodingException e) {
                // TODO: handle exception
            } catch (IOException e) {

            } finally {
                try {
                    is.close();
                } catch (IOException e) {

                }
            }
            return writer.toString();
        } else {
            return "";
        }
    }

    private String getResult(String response) {

        String test = "";
        try {
            JSONObject json = (JSONObject) new JSONTokener(response)
                    .nextValue();
            test = json.getString("responseCode");
        } catch (JSONException e) {

        }
        return test;
    }