坚持这一个。我想在"用户名"的密钥上传递2个表单输入。我想发送"用户名"和"位置"输入到我的PHP。可以这样做吗?尝试了一些事情,但无法弄清楚。
注意:当输入"用户名"时,我想传两个。
形式:
<fieldset>
<input name="location" type="text" id="location" maxlength="15">
<label for="username">Enter Username :
<input name="username" type="text" id="username" maxlength="15">
<span id="user-result"></span>
</label>
</div>
</fieldset>
脚本:
$(document).ready(function() {
$("#username").keyup(function (e) {
//removes spaces from username
//$(this).val($(this).val().replace(/\s/g, ''));
var username = $(this).val();
if(username.length < 4){$("#user-result").html('');return;}
if(username.length >= 4){
$("#user-result").html('<img src="../images/ajax-loader.gif" />');
$.post('check.php', {'username':username}, function(data) {
$("#user-result").html(data);
});
}
});
});
答案 0 :(得分:2)
只需从用户名keyup
事件处理程序中获取位置输入的值,并将其与请求一起传递:
$(document).ready(function() {
$("#username").keyup(function (e) {
//removes spaces from username
//$(this).val($(this).val().replace(/\s/g, ''));
var username = $(this).val();
var location = $('#location').val();
if(username.length < 4){$("#user-result").html('');return;}
if(username.length >= 4){
$("#user-result").html('<img src="../images/ajax-loader.gif" />');
$.post('check.php', { 'username':username, 'location': location}, function(data) {
$("#user-result").html(data);
});
}
});
});
答案 1 :(得分:1)
$("#username").on('keyup', function (e) {
// grab the elements we're interested in
var username = $(this).val(),
location = $("#location").val();
if (username.length > 3) {
$.ajax({
url: 'check.php',
type: 'POST',
data: {
username: username,
location: location
},
success: function (data) {
// do something after success
console.log(data)
},
error: function (jqXHR, textStatus, errorThrown) {
// deal with the error
console.log('status: ' + textStatus);
console.log('error: ' + errorThrown);
},
dataType: 'json' // or change to whatever you want
});
}
});