Question

我试图在C中制作一个程序，为用户提供一个预订学习室的菜单 1.预约房间
2.休息室
3.显示可用房间
退出
共有10间客房。我不确定如何在数组中使用更改值，其中0 ==房间打开，1 = =房间关闭。

#include <stdio.h>

void print_arr(int room[], int elements);
int search_arr(int room[], int elements, int open);

int main(void)
{
    int room[10] = { 1, 1, 1, 1, 1, 1, 1, 0, 0, 0 }; // array for 10 rooms
    int result, open;

    print_arr(room, 10);

    open = 0;

    result = search_arr(room, 10, open);

    if (result == -1)
        printf("There are no open rooms. \n");
    else 
        printf("There are %d vacant Rooms. ", result);

return 0;
}

void print_arr(int room[], int elements)
{
    int i;

    printf("Rooms: ");
    for (i = 0; i < elements; i++)
    {
        printf("%d ", room[i]);
    }
    printf("\n");
}

int search_arr(int room[], int elements, int open)
{
    int i;
    for (i = 0; i < elements; i++)
    {
        if (room[i] == open)

            printf("Vacant Room: %d \n", room[i]);
            return(open);   //found open rooms
    }
return(-1); //no open rooms found
}

Answer 1

您的搜索例程在每种情况下都返回0（这是打开的值），并且在找到的第一个打开的房间中执行此操作。要计算开放的房间，在看到每个元素之前都不能返回，每当你看到一个“开放”的房间时你就必须增加一个计数器。

int search_arr(int room[], int elements, int open)
{
  int i, openrooms=0;

  for (i = 0; i < elements; i++)
    if (room[i] == open)
      openrooms++;

  return openrooms; // returns 0 when none found...
}

Answer 2

您必须计算阵列中免费（开放）房间的数量，例如：

int search_arr(int room[], int elements, int open)
{
 int free = 0;
 int i;
 for (i = 0; i < elements; i++)
 {
    if (room[i] == open) {
        printf("Vacant Room number: %d \n", i);
        free++;
    }
 }
 return(free); // return number of vacant rooms; 0 if no rooms are free ;-)
}

Answer 3

search_arr函数中使用的逻辑是错误的。它应该是 -

int search_arr(int room[], int elements, int open)
{
    int i;
    for (i = 0; i < elements; i++)
    {
        if (room[i] == 0)

            {printf("Vacant Room No: %d \n", i);
            open++; //found open rooms
    }} if(open)
return(open);
return(-1); //no open rooms found
}

使用数组制作学习室预订程序

3 个答案: