Question

我想在每个组（由xy定义）的data.frame ID中绘制数据。当1946年之前的一年在一个小组中时，plot 2应该被执行。当年份在1946年至2014年之间时，应执行plot1。

我的问题：没有NA值就可以正常工作，但由于我有数据空白，我依靠NAs来定义这些数据空白。这就是我收到错误的原因：error in plot.window(need finite 'ylim' values)。我尝试将finite=T放在plot1的y轴上，但这会产生subscript out of bounds错误。有没有办法解决这个问题，图形是否正确绘制？

以下是我的代码：它很长但是大多数代码都包含我依赖的plot()选项。

# read in sample data and split it up by group (defined by ID)
xy <- data.frame(NAME=c("NAME2","NAME2","NAME2","NAME2","NAME2","NAME3","NAME3","NAME3","NAME3","NAME5","NAME5","NAME5","NAME5"), ID=c(48,48,48,48,48,32,32,32,32,67,67,67,67),YEAR=c(1981,1983,1984,1988,1989,1984,1984,1988,1988,1899,1933,1948,1958),VALUE=c(0,205,-570,0,-310,-3680,-3680,NA,-3680,0,NA,13,-98))
ind <- split(x = xy,f = xy[,'ID'])

# Plot Scenario 1: if only years between 1946 and 2014 are present for each group do this:
  plot1 <- function(x) {
  fname <- paste0(x[1, 'ID'], '.png')
  png(fname, width=1679, height=1165, res=150)
  par(mar=c(6,8,6,5))
  plot(x = c(1946, 2014),
       y = range(x$VALUE),
       type='n',
       main=x[1, 'NAME'],
       xlab="Time [Years]",
       ylab="Value")
  axis(2, at = seq(-100000, 100000, 500), cex.axis=1, labels=FALSE, tcl=-0.3)
  points(ind[[i]][,c('YEAR','VALUE')], type="l", lwd=2)
  points(ind[[i]][,c('YEAR','VALUE')], type="p", lwd=1, cex=1,   pch=21, bg='white')
  abline(h=0)
  dev.off()
}

# Plot Scenario 2 if years under 1946 are present do this:
plot2 <- function(x) {
  fname <- paste0(x[1, 'ID'], '.png')
  png(fname, width=1679, height=1165, res=150)    
  par(mar=c(6,8,6,5))
  plot(x[,c('YEAR','VALUE')],
       type='n',
       main=x[1, 'NAME'],
  xlab="Time [Years]",
  ylab="Value [mm]")
axis(2, at = seq(-100000, 100000, 500), cex.axis=1, labels=FALSE, tcl=-0.3)
points(ind[[i]][,c('YEAR','VALUE')], type="l", lwd=2)
points(ind[[i]][,c('YEAR','VALUE')], type="p", lwd=1, cex=1,   pch=21, bg='white')
abline(h=0)
dev.off() 
}

# Execute functions
    lapply(ind, function(x) ifelse(any(x$YEAR < 1946 & x$YEAR < 2014), plot2(x), plot1(x)))

Answer 1

在plot1中，将y = range(x$VALUE)更改为y = range(x$VALUE, na.rm=TRUE)以删除NA个缺失值。

你有另一个问题，即你在两个函数中引用ind[[i]]，我认为这意味着在某些时候这段代码是循环的一部分。我的猜测是ind[[i]]的所有引用都应该是x。

R：在函数中需要有限的'ylim'值

1 个答案: