Question

您好我正在尝试创建一个循环，以便当有人在我的代码中死亡时它会停止，同样代码也不会结束直到有人死亡（也就是说，有强度或技能达到零）然而，无论如何我投入了多少数字，游戏总是无限延续。

我该如何解决这个问题？

while True:
    try:
        strengthA=abs(int(input("enter strength A ")))
        break          
    except ValueError:
        print("Error")
        print ("value entered")
while True:
    try:

        strengthB=abs(int(input("enter strength B ")))
        break
    except ValueError:
        print("Error")
        print ("value entered successfully")

while True:
    try:
        skillA=abs(int(input("enter skillA ")))
        break
    except ValueError:
        print("Error")
        print ("value entered successfully ")

while True:
    try:
        skillB=abs(int(input("enter skill B ")))
        break
    except ValueError:
        print("Error")
        print ("value entered successfully")



strengthmod=abs(int((strengthA-strengthB)/5))
print (strengthmod)
skillmod=abs(int((skillA-skillB)/5))
print(skillmod)


while strengthA>0 and strengthB>0:
    print strengthA, strengthB
    import random
    throwA=int(random.randrange(6)+1)
    print("Cloudy throws "+str(throwA))
    throwB=int(random.randrange(6)+1)
    print("Mocha throws "+str(throwB))

    if throwA>throwB:

        print("Cloudy wins!")
        skillA=skillA+skillmod
        strengthA=strengthA+strengthmod
        skillB=skillB-skillmod
        strengthB=strengthB-strengthmod
    elif throwA<throwB:
        print("Mocha wins!")
        skillA=skillA-skillmod
        strengthA=strengthA-strengthmod
        skillB=skillB+skillmod
        strengthB=strengthB+strengthmod
    else:
        print ("No one wins")


    if skillA<1:
        skillA=0
    if skillB<1:
        skillB=0
    print("Cloudy new skill " +str(skillA))
    print("Mocha new skill " +str(skillB))
    print("Cloudy new strength " +str(strengthA))
    print("Mocha new strength " +str(strengthB))
    if strengthA<1:
        print ("Cloudy dies")
    if strengthB<1:
        print ("Mocha dies")
    print ("Battle ends")

Answer 1

如果strengthA和strengthB彼此靠近，strengthmod将为0：

strengthmod=abs(int((strengthA-strengthB)/5))

所以strengthA和strengthB永远不会改变：

...
strengthB=strengthB-strengthmod
...
strengthA=strengthA-strengthmod
...

所以while循环

while strengthA>0 and strengthB>0:

永远运行。

即使strengthA为strengthB，也许您应该确保strengthmod和0会发生变化，例如：

strengthB=strengthB-max(strengthmod, 1)

循环代码：无限如何阻止这个

1 个答案: