Question

我在CI中遇到此错误：

A PHP Error was encountered
Severity: Notice
Message:  Undefined variable: loai
Filename: views/thembds.php
Line Number: 57

A PHP Error was encountered
Severity: Warning
Message:  Invalid argument supplied for foreach()
Filename: views/thembds.php
Line Number: 57

我的控制器：

public function loaibds() 
        {    
             $this->load->model('admin_model');
             $data['loai'] = $this->admin_model->loai();
             $this->load->view('thembds', $data);        
        }

我的模特：

public function loai()
            {
                 $l = $this->db->query("SELECT * FROM loaibds");

                 if($l->num_rows() > 0)
                     return $l->result();
                 return false;
            }

我的观点：

<select class="form-control" name="loai">
 <?php foreach($loai as $l) { ?>
<option value="<?php echo $l->id; ?>"> <?php echo $l->loai; ?> </option>
<?php } ?>  
  </select>

我有什么错误？我想在视图页面上分配行和回显，例如

Answer 1

             $l = $this->db->get('loaibds')->result();

             if($l->num_rows() > 0)
                 return $l;
           }

Answer 2

因为$l->result()是资源，而不是结果。

将模型更改为以下内容：

public function loai()
        {
             $l = $this->db->query("SELECT * FROM loaibds");

             $result = array();
             if($l->num_rows() > 0)
                   foreach ($l->result() as $row)
                       $result = $row;
             return $result;
        }

现在应该可以了。

Answer 3

更改模型

$l = $this->db->get('loaibds');
if($l->num_rows()>0)
{
   return $l->result();
}
else{

    return FALSE;
}

Codeigniter：Foreach来查看

3 个答案: