我需要使用JSP将图像文件上传到服务器。
我在这里使用纯Ajax而不是Jquery。我还没有使用FORM提交，因为我不想刷新当前页面。
这是我尝试过的。
的Page1.jsp
<table width="60%" border="0" cellspacing="1" cellpadding="1" align="center" class="style1">
<tr>
<td align="left"><b>Select a file to upload :</b></td>
</tr>
<tr>
<td align="left">
<input type="file" name="file" id="listfile" onchange="readURL(this);">
</td>
</tr>
<tr>
<td align="left">
<input type="submit" value="SUBMIT" />
</td>
</tr>
</table>
<script>
function readURL(input)
{
if (input.files && input.files[0])
{
var reader = new FileReader();
reader.onload = function (e)
{
$('#img_prev').attr('src', e.target.result).width("25%").height("25%");
};
reader.readAsDataURL(input.files[0]);
}
}
</script>
现在我需要做的是从＆＃34; page1.jsp＆＃34;发送此文件。 to＆＃34; page2.jsp＆＃34;。我已经尝试过使用它很好的工作，但我不希望用户更改当前页面。
以下是page2.jsp的代码
page2.jsp
<%@ page import="java.io.*,javax.servlet.http.HttpServletRequest,javax.servlet.ServletInputStream" %>
<%@ page import="java.io.FileWriter,java.io.IOException" %>
<%
String savePath = "", filepath = "", filename = "";
String contentType = "", fileData = "", strLocalFileName = "";
int startPos = 0, endPos = 0;
int BOF = 0, EOF = 0;
%>
<%! void copyByte(byte [] fromBytes, byte [] toBytes, int start, int len)
{
for(int i=start;i<(start+len);i++)
{
toBytes[i - start] = fromBytes[i];
}
}
%>
<%
contentType = request.getContentType();
out.println("<br>Content type is :: " +contentType);
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0))
{
DataInputStream in = new DataInputStream(request.getInputStream());
DataInputStream in1 = in;
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength)
{
byteRead = in1.read(dataBytes, totalBytesRead, formDataLength);
totalBytesRead += byteRead;
}
out.println("<br>totalBytesRead : " + totalBytesRead + " : formDataLength = " + formDataLength);
byte[] line = new byte[128];
if (totalBytesRead < 3)
{
return; //exit if file length is not sufficiently large
}
String boundary = "";
String s = "";
int count = 0;
int pos = 0;
do
{
copyByte(dataBytes, line, count ,1); //read 1 byte at a time
count+=1;
s = new String(line, 0, 1);
fileData = fileData + s;
pos = fileData.indexOf("Content-Disposition: form-data; name=\"");
if(pos != -1)
endPos = pos;
}while(pos == -1);
boundary = fileData.substring(startPos, endPos);
startPos = endPos;
do
{
copyByte(dataBytes, line, count ,1); //read 1 byte at a time
count+=1;
s = new String(line, 0, 1);
fileData = fileData + s;
pos = fileData.indexOf("filename=\"", startPos); //set the file name
if(pos != -1)
startPos = pos;
}while(pos == -1);
do
{
copyByte(dataBytes, line, count ,1); //read 1 byte at a time
count+=1;
s = new String(line, 0, 1);
fileData = fileData + s;
pos = fileData.indexOf("Content-Type: ", startPos);
if(pos != -1)
endPos = pos;
}while(pos == -1);
filename = fileData.substring(startPos + 10, endPos - 3);
strLocalFileName = filename;
String[] NewName = filename.split("\\.");
out.println("Original File Name is:"+filename);%><br><%
String rename = "newName";
String NewName1 = rename+"."+NewName[1];
out.println("New File Name is:"+NewName1);%><br><%
filename = NewName1;
int index = NewName1.lastIndexOf("\\");
if(index != -1)
{
%>
<script language="javascript">
alert("File already Exists!");
</script>
<%
NewName1 = NewName1.substring(index + 1);
}
else
{
NewName1 = NewName1;
}
boolean blnNewlnFlag = false;
startPos = endPos; //added length of "Content-Type: "
do
{
copyByte(dataBytes, line, count ,1);
count+=1;
s = new String(line, 0, 1);
fileData = fileData + s;
pos = fileData.indexOf("\n", startPos);
if(pos != -1)
{
if(blnNewlnFlag == true)
endPos = pos;
else
{
blnNewlnFlag = true;
pos = -1;
}
}
}while(pos == -1);
contentType = fileData.substring(startPos + 14, endPos);
BOF = count + 1;
do
{
copyByte(dataBytes, line, count ,1); //read 1 byte at a time
count+=1;
s = new String(line, 0, 1);
fileData = fileData + s;
pos = fileData.indexOf(boundary, startPos);
}while(pos == -1);
EOF = count - boundary.length();
out.println("<br><br>0. Local File Name = " + strLocalFileName);
out.println("<br><br>1. FILE-NAME-CHANGE = " + NewName1);
out.println("<br>2. contentType = " + contentType);
out.println("<br>3. startPos = " + BOF);
out.println("<br>4. endPos = " + EOF);
out.println("<br>5. boundary = " + boundary);
String appPath = application.getRealPath("/");
out.println("<br>appPath : " + appPath);
String destFolder = appPath + "images/"; //change this as required
NewName1= destFolder + NewName1;
FileOutputStream fileOut = new FileOutputStream(NewName1);
fileOut.write(dataBytes, BOF, (EOF - BOF));
fileOut.flush();
fileOut.close();
out.println("<br>File saved as >> " + NewName1);
}
else
{
out.println("Error in uploading ");
}
%>
我需要做的就是不使用表单并使用AJAX发送图像文件。
**or**
上传而不刷新整个页面的任何其他方式