Question

学习编码，并为数字猜谜游戏尝试了一个简单的while循环。这个想法是，如果错误猜测的数量达到5，那么它将导致循环变为“错误”＃34;并结束。相反，它将循环，直到它被测试站点作为无限循环结束。＆＃34;休息＆＃34;虽然版本工作得很好。我的问题是为什么if＆＃34; break＆＃34;工作，但||值为set = false不起作用？

无效的代码段

while (secret != guess || wrong < 5)
{
    if (guess < secret)
    {
        printf("You guessed too low\n");
        wrong++;
    }
    else 
    {
        printf("you guessed too high\n");
        wrong++;
    }
    printf("Input another guess\n");
    scanf ("%d", &guess);

}

工作代码段

while (secret != guess)
{
    if (guess < secret)
    {
        printf("You guessed too low\n");
    }
    else 
    {
        printf("you guessed too high\n");
    }
    printf("Input another guess\n");
    scanf("%d", &guess);
    wrong = wrong + 1;
    if (wrong >= 5)
    {
        break;
    }
}

Answer 1

while表达式可以通过两种方式“翻译”：

只要条件成立
直到情况变为虚假

您似乎对某种稍微复杂的情况存在逻辑混淆。

更改此内容：

while (secret != guess || wrong < 5)
// until both of the conditions become false
// as long as either one of the conditions is true

到此：

while (secret != guess && wrong < 5)
// as long as both of the conditions are true
// until either one of the conditions becomes false

为什么＆＃34;或＆＃34;这部分声明虽然不起作用，但是破坏声明呢？（对于C）

1 个答案: