Question

我需要在当周的每一天内计算项目。不幸的是，这个选择不起作用我想...

感谢您的帮助

SELECT strftime('%d', data_item/1000, 'unixepoch') AS valDay,
    SUM(numero_item) AS totalDAY
FROM table
WHERE
    strftime('%Y', data_item/1000, 'unixepoch') = strftime('%Y', 'now')
    AND strftime('%m', data_item/1000, 'unixepoch') = strftime('%m', 'now')
    GROUP BY valDay

EDIT I've added the solution (localtime) for future reference:
strftime('%Y', data_item/1000, 'unixepoch''localtime') = strftime('%Y', 'now')

Answer 1

你试过吗

SELECT strftime('%d', data_item/1000, 'unixepoch') AS valDay,
SUM(numero_item) AS totalDAY
FROM table
WHERE
 strftime('%Y', data_item/1000, 'unixepoch') = strftime('%Y', 'now')
 AND strftime('%m', data_item/1000, 'unixepoch') = strftime('%m', 'now')
 GROUP BY strftime('%d', data_item/1000, 'unixepoch')

并非所有语言都支持稍后在查询中使用别名（如valDay）

本周每天的Android Sqlite Count项目

1 个答案: