Question

我尝试正常更新属性，但它没有更新。

这是我的客户模型

    class Customer < ActiveRecord::Base
      attr_accessible :name, :phone_number, :email
      attr_accessible :first_name
      attr_accessible :last_name

      before_validation :parse_name
      def name
         "#{first_name} #{last_name}".strip
      end

  private

  def parse_name
    if attributes['name'].present?
      self.first_name, self.last_name = attributes['name'].strip.split(' ', 2)
    end
  end
end

我尝试更新first_name和last_name，但它没有更新，但是如果我尝试更新电子邮件则更新正常

这是我的rails控制台跟踪 更新电子邮件

2.1.0dev :004 > a = Customer.find(5)
  Customer Load (0.2ms)  SELECT `customers`.* FROM `customers` WHERE `customers`.`id` = 5 LIMIT 1
 => #<Customer id: 5, name: "First Last", phone_number: "1234567890", created_at: "2014-09-15 12:48:30", updated_at: "2014-09-15 14:32:17", first_name: "Fir
2.1.0dev :008 > a = Customer.find(5)
  Customer Load (0.1ms)  SELECT `customers`.* FROM `customers` WHERE `customers`.`id` = 5 LIMIT 1
 => #<Customer id: 5, name: "First Last", phone_number: "1234567890", created_at: "2014-09-15 12:48:30", updated_at: "2014-09-15 14:32:17", first_name: "Fir
st", last_name: "Last", email: "shri@mail.com"> 
2.1.0dev :009 > a.email = "Test@test.com"
 => "Test@test.com" 
2.1.0dev :010 > a.save
   (0.2ms)  BEGIN
  Customer Exists (0.2ms)  SELECT 1 AS one FROM `customers` WHERE (`customers`.`phone_number` = BINARY '1234567890' AND `customers`.`id` != 5) LIMIT 1
   (0.4ms)  UPDATE `customers` SET `email` = 'Test@test.com', `updated_at` = '2014-09-15 20:38:31' WHERE `customers`.`id` = 5
   (104.9ms)  COMMIT
 => true 
2.1.0dev :011 > a
 => #<Customer id: 5, name: "First Last", phone_number: "1234567890", created_at: "2014-09-15 12:48:30", updated_at: "2014-09-15 20:38:31", first_name: "Fir
st", last_name: "Last", email: "Test@test.com">

但是更新first_name并且last_name不起作用

更新last_name

2.1.0dev :012 > a.last_name = "last_name"
 => "last_name" 
2.1.0dev :013 > a.save
   (0.2ms)  BEGIN
  Customer Exists (0.7ms)  SELECT 1 AS one FROM `customers` WHERE (`customers`.`phone_number` = BINARY '1234567890' AND `customers`.`id` != 5) LIMIT 1
   (0.2ms)  COMMIT
 => true 
2.1.0dev :014 > a.save!
   (0.2ms)  BEGIN
  Customer Exists (0.2ms)  SELECT 1 AS one FROM `customers` WHERE (`customers`.`phone_number` = BINARY '1234567890' AND `customers`.`id` != 5) LIMIT 1
   (0.1ms)  COMMIT
 => true 
2.1.0dev :015 > a
 => #<Customer id: 5, name: "First Last", phone_number: "1234567890", created_at: "2014-09-15 12:48:30", updated_at: "2014-09-15 20:38:31", first_name: "Fir
st", last_name: "Last", email: "Test@test.com">

使用更新属性

2.1.0dev :016 > a.update_attributes(:first_name => "test_name", :last_name => "test_name")
   (0.2ms)  BEGIN
  Customer Exists (0.2ms)  SELECT 1 AS one FROM `customers` WHERE (`customers`.`phone_number` = BINARY '1234567890' AND `customers`.`id` != 5) LIMIT 1
   (0.2ms)  COMMIT
 => true 
2.1.0dev :017 > a
 => #<Customer id: 5, name: "First Last", phone_number: "1234567890", created_at: "2014-09-15 12:48:30", updated_at: "2014-09-15 20:38:31", first_name: "Fir
st", last_name: "Last", email: "Test@test.com">

我试图解决它，但它无法正常工作。可以请告诉我我错过了什么。我正在使用rails 3.2.14 and rails 2.1.0

Answer 1

您有 before_validation 方法，其中根据名称设置名字和姓氏。您的记录已有名称，因此它会拆分此名称并提取名字和姓氏。

Answer 2

您的before_validation正在覆盖您要设置的值。我会一起删除解析名称方法，并使#name方法只是基于first_name和last_name的计算值，例如

class Customer < ActiveRecord::Base
  attr_accessible :phone_number, :email, :first_name, :last_name
  def name
     "#{first_name} #{last_name}".strip
  end
end

如果你真的必须#name=我会这样做

def name=(name_string)
   self.first_name, self.last_name = name_string.strip.split(' ', 2)
end

您必须save才能保留这些值。你也可以这样做。

def update_name(name_string)
  update_attributes(Hash[[:first_name,:last_name].zip(name_string.strip.split(' ', 2))])
end

哪个会与save一起运行，并根据有效性返回true或false

rails 3中没有更新值

2 个答案: