有人可以帮助我将这个sql转换为symfony吗?
SELECT cl.* from computador_coleta cl inner join class_property p on cl.id_class_property = p.id_class_property where p.id_class = 15 AND cl.id_computador = 2510;
cl.id_computador是一个变量。
答案 0 :(得分:3)
$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
'SELECT cc FROM CacicCommonBundle:ComputadorColeta cc INNER JOIN CacicCommonBundle:ClassProperty cp WITH cc.classProperty = cp.idClassProperty WHERE cp.idClass = 15 AND cc.computador = :id'
)->setParameter('id', $computador);
$result = $query->getResult();
答案 1 :(得分:0)
$em = $this->getDoctrine()->getManager();
$qb = $em->createQueryBuilder();
$result = $qb->select('c')
->from('CacicCommonBundle:ComputadorColeta','cc')
->innerJoin('cc.classProperty','cp')
->where('cp.idClass = :idClass')
->andWhere('cc.idComputador = :idComputador')
->setParameter('idClass', 15)
->setParameter('idComputador', 2510)
->getQuery()
->getOneOrNullResult();
if(!$result) {
throw new \Exception('no results')
}
我建议使用类似于教条的内容,因为它更容易阅读