我正在尝试将切换功能应用到我正在处理的程序中。具体而言,用户单击按钮时有3种可能的情况。
我无法实现此功能。到目前为止,这是我的代码:
var toolState = {
img_draw_point: false,
img_draw_line: false,
img_draw_rectangle: false,
img_draw_ellipse: false,
img_draw_FreehandPolygon: false,
img_draw_FreehandPolyline: false,
img_draw_text: false,
img_draw_eraser: false,
};
var lastActiveTool;
on(dom.byId("div-tools-draw"), "click", function (evt) {
function disableActiveCSS() {
for (var property in toolState) {
$("img#" + property + ".k-button.single").removeClass("buttonSelected");
$("img#" + property + ".k-button.single").removeClass("buttonHoverState");
}
}
function enableCSS() {
$("img#" + evt.target.id + ".k-button.single").addClass("buttonSelected");
$("img#" + evt.target.id + ".k-button.single").addClass("buttonHoverState");
}
toolState[evt.target.id] = !toolState[evt.target.id];
if (toolState[evt.target.id] == toolState[lastActiveTool]) {
toolState[lastActiveTool] = false;
}
disableActiveCSS();
enableCSS();
if (evt.target.id == lastActiveTool) {
disableActiveCSS();
}
}
非常感谢任何帮助。
答案 0 :(得分:1)
我看到你的代码包含'$'符号,所以我在回复中使用了jQuery。它还假设我们只关心另一个工具当前是否“开启”。所以我的回答中的3个选项是:
var lastActiveTool = false;
$.click("#div-tools-draw", function(evt) {
// Disable Active CSS
$("img.k-button.single").removeClass("buttonSelected").removeClass("buttonHoverState");
if (!lastActiveTool) {
activateTool(evt.target.id);
} else if (evt.target.id == lastActiveTool) {
sameToolToggle(evt.target.id);
} else {
otherToolToggle(evt.target.id);
}
};
var activateTool = function (id) {
$("img#" + id + ".k-button.single").addClass("buttonSelected")addClass("buttonHoverState");
lastActiveTool = evt.target.id;
};
var otherToolToggle = function(id) {
$("img#" + id + ".k-button.single").addClass("buttonSelected")addClass("buttonHoverState");
lastActiveTool = evt.target.id;
// Whatever else you need to do to toggle between tools
}
// Only gets called when the same tool is currently toggled ON
var sameToolToggle = function(id) {
lastActiveTool = false;
}