Question

shell脚本应该在单行输入中采用多个条件，并且应该使用输入字符的一端来执行下一个操作。即。

#!/bin/bash
#Functions are defined here 1 2 3 4 5


echo "choice"
echo 
echo "[1] one"
echo "[2] two"
echo "[3] three"
echo "[4] four"
echo "[5] five"
echo
read -p "Enter choice:  " ch
        if [ "$ch" = "1" ]; then
        function_1
        else
        if [ "$ch" = "2" ]; then
        function_2
        else
        if [ "$ch" = "3" ]; then
        function_3
        else
        if [ "$ch" = "4" ]; then
        function_4
        else
        if [ "$ch" = "5" ]; then
        function_5
fi
fi
fi
fi
fi

现在说输入结束表示为＆＃39; e＆＃39;因此，如果我执行.sh文件并在＆＃34;输入选项＆＃34;

$Enter choice: 1 3 5 e

它应该逐个执行1 3和5功能怎么做？

Answer 1

您可以迭代所有选项，直到找到输入的结尾＆＃39;：

read -p "Enter choice:  " ch

for choice in $ch; do
    [ "$choice" == 'e' ] && break
    eval function_$choice
done

注意：eval将从参数汇编命令，然后通过shell

执行它

Answer 2

你应该迭代你的字符串ch直到＆＃34; e＆＃34;出现：

#!/bin/bash
#Functions are defined here 1 2 3 4 5


echo "choice"
echo 
echo "[1] one"
echo "[2] two"
echo "[3] three"
echo "[4] four"
echo "[5] five"
echo
read -p "Enter choice:  " ch

for i in ${ch}
do
  if [ "$i" == "1" ]; then
    function_1
  else if [ "$i" == "2" ]; then
    function_2
  else if [ "$i" == "3" ]; then
    function_3
  else if [ "$i" == "4" ]; then
    function_4
  else if [ "$i" == "5" ]; then
    function_5
  else if [ "$i" == "e" ]; then
    break
fi
fi
fi
fi
fi
fi

但是mxlian的答案是＆＃34;更清洁＆＃34;。我只是更正你的代码..

Answer 3

如果您将每个输入参数作为选项并使用了getopts即

，那会更好

myProg.sh -a aArg -b bArg -c cArg

在myProg.sh中：

while getopts "a:b:c" option
do
    case $option in
    a) function_1;;
    b) function_2;;
    c) function_3;;
    *) exitFunc "Incorrect argument";;   # You need to write exitFunc()
    esac
done

这样你可以有一个缺失的选项，即只有选项a和c（没有b）。如果按照自己的方式进行，并且缺少一个参数（或为空），则说参数3，则参数4变为参数3等。

Shell脚本在单个文件中接受多个用户输入

3 个答案: