Question

以下是用于在BluetoothChat Code中接收和显示数据的代码段。我想组合（连接）两个连续的值并将其显示为一个值。这可能吗？

BluetoothChat.java

// The Handler that gets information back from the BluetoothChatService
private final Handler mHandler = new Handler() {
    @Override
    public void handleMessage(Message msg) {
        switch (msg.what) {

          case MESSAGE_READ:

           byte[] readBuf = (byte[]) msg.obj;       

           String readMessage = new String(readBuf, 0, msg.arg1);

           mConversationArrayAdapter.add(readMessage);

           break;
           }
             }
              }

Answer 1

试试这个：它会将新项目添加到上一个列表的末尾。

 mConversationArrayAdapter.addAll(readMessage);

Answer 2

如果是每两条消息，这是一个解决方法：

// The Handler that gets information back from the BluetoothChatService
private final Handler mHandler = new Handler() {
    @Override
    public void handleMessage(Message msg) {
    int c = 0;
    String s ="";
        switch (msg.what) {


       case MESSAGE_READ:

          byte[] readBuf = (byte[]) msg.obj;       

           String readMessage = new String(readBuf, 0, msg.arg1);
           c++;
           s += readMessage;
           if(c==2) {
           mConversationArrayAdapter.add(readMessage);
           c=0;
           s=""
           }

           break;
       }}}

如何连接在数组适配器中获得的两个连续值？

2 个答案: