Question

我试图建立评论系统。当我的表单发布时，并调用我的动作创建＆＃39;功能。我在firebug上收到错误。但数据存储在我的数据库中。我知道我做错了什么？

这是我在我的控制器中的动作

    public function actionCreate()
    {

         /** @var Comment $comment */
         $comment = Yii::createComponent($this->module->commentModelClass);

        // Uncomment the following line if AJAX validation is needed
         $user=new User;

         $this->performAjaxValidation(array($comment, $user));
         //end of Ajax validation

        $_user = Yii::app()->request->getPost('User');

        if(isset($_POST[$cClass=get_class($comment)], $_user))
        {
            $comment->attributes = $_POST[$cClass];
            //$comment->type = $_POST[$cClass]['type'];
            //$comment->key  = $_POST[$cClass]['key'];

            $user->attributes = $_user;

            // determine current users id
            if (Yii::app()->user->isGuest) {
                $comment->userId = null;
            } else {
                $comment->userId = Yii::app()->user->id;
            }

            if(Yii::app()->request->isAjaxRequest) 
            {
                /* the error happens here */
                if($comment->save())
                {
                    // refresh model to replace CDbExpression for timestamp attribute
                    $comment->refresh();

                    // create new comment model for empty form
                    $comment = Yii::createComponent($this->module->commentModelClass);
                    //$comment->type = $_POST[$cClass]['type'];
                    //$comment->key  = $_POST[$cClass]['key'];
                }
                else { 
                     //Return messages from try/catch
                    echo CJSON::encode(array(
                        'msg' => 'Check your form, and fill up all required fields'
                    ));
                }

                Yii::app()->end();

            } 
            else 
            {
                if($comment->save()) {
                    $this->redirect(isset($_POST['returnUrl']) ? $_POST['returnUrl'] : array('view','id'=>$comment->id));
                } 
                else {
                     //Return messages from try/catch
                    echo CJSON::encode(array(
                        'msg' => 'Check your form, and fill up all required fields'
                    ));
                }

                Yii::app()->end();
            }
        }

    }

我的评论对象

我得到的错误

 <b>Fatal error</b>:  Class name must be a valid object or a string in <b>/Library/WebServer/Documents/dev/common/lib/yii/framework/db/ar/CActiveRecord.php</b> on line <b>395</b><br />

这里是CActiveRecord.php

public static function model($className=__CLASS__)
    {
        if(isset(self::$_models[$className]))
            return self::$_models[$className];
        else
        {
            $model=self::$_models[$className]=new $className(null); //this is line 395
            $model->attachBehaviors($model->behaviors());
            return $model;
        }
    }

Answer 1

这就是我的案例中评论的方式：

public function actionCreate(){

    $comment = new Comment;

    if($_POST[get_class($comment)]){
        // save data here 
        if ( $comment->save() ) {
            // comment saved !!
        } else {
            // comment not saved
        }
    }

    $this->render('new',array('comment'=>$comment));
}

在您的情况下，评论是一个组件而不是模型如果要检查表单是否已提交，则不是我所知道的。

评论模型的示例：

class Comment extends CActiveRecord
{
    $id;

    public static function model($className=__CLASS__)
    {
        return parent::model($className);
    }

    public function rules(){
    }
}

$ model-＆gt; save（）给我一个错误

1 个答案: