昨晚我试图解决这个问题,但没有运气,所以我希望你们可以提供帮助,因为我想出了所有的想法:
我有两个父表,我想从中填充一个Junction表:
新娘:
create table if not exists `Brides` (
`BrideID` INT not null auto_increment,
`MaidenName` varchar(10) unique,
primary key (`BrideID`)
) engine=InnoDB;
insert into Brides (MaidenName)
values ('Smith'),
('Jones')
;
教会:
create table if not exists `Churches` (
`ChurchID` INT not null auto_increment,
`ChurchName` varchar(10) unique,
primary key (`ChurchID`)
) engine=InnoDB;
insert into Churches (ChurchName)
values ('St Marys'),
('St Albans')
;
我试图通过间接引用每个父表中的唯一名称来填充Junction表 Marriages 的ID变量。此外,我希望包含MarriedName
以确定新娘是否结婚不止一次:
婚姻:
create table if not exists 'Marriages' (
'BrideID' INT not null,
'ChurchID' INT not null,
'MarriedName' TEXT not null
primary key ('BrideID','ChurchID','MarriedName')
INDEX `fk_Marriages_Brides1_idx` (`BrideID` ASC),
INDEX `fk_Marriages_Churches1_idx` (`ChurchID` ASC),
CONSTRAINT `fk_Marriages_Brides1`
FOREIGN KEY (`BrideID`)
REFERENCES `Brides` (`BrideID`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_Marriages_Churches1`
FOREIGN KEY (`Church_ID`)
REFERENCES `Churches` (`ChurchID`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
;
我尝试做类似下面的伪代码(虽然我很确定它无论如何都不是聪明的方法,因为必须要有这么多的子-queries):
insert into Marriages (Bride_ID, Church_ID, MarriedName)
select b.BrideID, c.ChurchID, m.MarriedName
from (values (Bride,Church,MarriedName)
('Smith','St Marys','Johnson'),
('Jones','St Albans','Peterson')
) m
join Brides b
on a.MaidenName=m.Bride
join Churches c
on m.Church=c.ChurchName;
非常感谢您的任何帮助/见解/更正!
答案 0 :(得分:1)
尝试一下:
INSERT INTO Marriages
SELECT b.BrideID, c.ChurchID, 'Johnson'
FROM Brides b, Churches c
WHERE b.MaidenName='Smith' AND c.ChurchName='St Marys'
答案 1 :(得分:0)
为了完整起见,我想分享这个解决方案,以防它帮助其他人......第一步也是最后一步不需要改变,只需要原始的'第二步中的数据需要添加到:
create table if not exists `_marriages` (
`BrideName` varchar(10) null,
`ChurchName` varchar(10) null,
`MarriedName` varchar(10) NULL,
primary key (`BrideName`,`ChurchName`,`MarriedName`))
engine=InnoDB
;
insert into `_marriages` (BrideName,ChurchName,MarriedName)
values
('Smith','St Albans','Johnson'),
('Jones','St Marys','Peterson')
;
insert into `Marriages` (Bride_ID, Church_ID, MarriedName)
select distinct b.BrideID, c.ChurchID, a.MarriedName
from _marriages a
inner join Brides b
on (a.BrideName=b.MaidenName)
left join Churches c
on a.ChurchName=c.ChurchName
;
...一如既往,如果有人在更好的方式上取得任何进展,请告诉我们!