错误：无效操作数到二进制*（有'int'和'* int'）我的代码有什么问题？

Question

#include <stdio.h>

void swap(int *a, int *b, int *c);

int main(void)
{
    int a, b, c;
    printf("Enter three numders: ");
    scanf("%d", &a, &b, &c);
    swap(&a, &b, &c);
    printf("The numders reordered: %d %d %d\n", a, b, c);
    return 0;
}

void swap(int *a, int *b, int *c)
{
    int temp;
    if(*a > *b && *a > *c)
    {
        *a = *a;
        if(*b > *c)
        {
            *b = *b;
            *c = *c;
        }
        else
        {
            temp = *b;
            *b = *c;
            *c = temp;
        }
    }
    else if(*b > *a && *b > *c)
    {
        temp = *a;
        *a = *b;
        if(*a > *c)
        {
            *b = temp;
            *c = *c;
        }
        else
        {
            *b = *c
            *c = temp;
        }
    }
    else
    {
        temp = *a;
        *a = *c;
        if(*a > *b)
        {
            *c = *b;
            *b = temp;
        }
        else
        {
            *b = *c;
            *c = temp;
        }
    }
    return;
}

Answer 1

您在第44行忘了;

else
{
    *b = *c //<<<<<
    *c = temp;
}

在预处理阶段，所有换行都将被删除，编译器会尝试理解这个表达式：

*b = *c*c=temp