Question

我有3个标签，其中一个标签上有联系方式的列表视图，无法使其正常工作。

listview位于片段布局中，ID为 list 。我在尝试访问该标签时遇到此错误：

java.lang.ArrayIndexOutOfBoundsException: length=2; index=2 at com.gabrielfiocchi.packemovilvq.ListaParaTabContacto.getView(ListaParaTabContacto.java:42)

This有效，但不适用于此自定义适配器。

以下代码：

TabContacto.java

import android.support.v4.app.Fragment;
import android.os.Bundle;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class TabContacto extends Fragment{

String[] web = {
        "Correo",
        "Twitter",
        "Teléfono"
} ;
String[] datos = {
        "info@somemail.com",
        "@sometwitter",
        "+0123456789"
} ;
Integer[] imageId = {
        R.drawable.img_mail,
        R.drawable.img_twitter,
};

ListView lv;
@Override
public View onCreateView(LayoutInflater inflater, 
        ViewGroup container, Bundle savedInstanceState) {
    View v = inflater.inflate(R.layout.fragment_contacto, container, false);
    perform(v);
    return v;
}

public void perform(View v) {
    lv = (ListView) v.findViewById(R.id.list);

    ListaParaTabContacto adapter = new ListaParaTabContacto(getActivity(), web, datos, imageId);
    lv.setAdapter(adapter);
}
}

这是我的自定义适配器： ListaParaTabContacto

import android.app.Activity;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.ImageView;
import android.widget.TextView;

public class ListaParaTabContacto extends ArrayAdapter<String> {

    private final Activity context;
    private final String[] web;
    private final String[] datos;
    private final Integer[] imageId;

    public ListaParaTabContacto(Activity context,
                                String[] web, String[] datos, Integer[] imageId) {
        super(context, R.layout.list_single, web);
        this.context = context;
        this.web = web;
        this.datos = datos;
        this.imageId = imageId;
    }

    @Override
    public View getView(int position, View view, ViewGroup parent) {
        LayoutInflater inflater = context.getLayoutInflater();
        View rowView = inflater.inflate(R.layout.list_single, null, true);
        TextView txtTitle = (TextView) rowView.findViewById(R.id.txt);
        TextView txtTitle2 = (TextView) rowView.findViewById(R.id.txt2);

        ImageView imageView = (ImageView) rowView.findViewById(R.id.img);
        txtTitle.setText(web[position]);
        txtTitle2.setText(datos[position]);

        imageView.setImageResource(imageId[position]);
        return rowView;
    }
}

提前致谢！

Answer 1

问题是imageId数组只有2个值。

ArrayAdapter构造函数的第三个参数是要在ListView中显示的元素。因此，基于web数组，Adapter中有3个元素。

当ListView构造的最后一个元素position = 2时，您访问位置无效的imageId数组，抛出ArrayIndexOutOfBoundsException。

您必须向imageId添加一个项目或移除web数组的任何元素（ListView将包含2个元素）或在访问其位置之前检查position < imageId.length是否

无法使listview与片段一起使用

1 个答案: