这个例子中是否有内存泄漏？

Question

来自官方D书：

import std.stdio;

void main()
{
    double[] slice1 = [ 1, 1, 1 ];
    double[] slice2 = [ 2, 2, 2 ];
    double[] slice3 = [ 3, 3, 3 ];

    slice2 = slice1;      // ← slice2 starts providing access
                          //   to the same elements that
                          //   slice1 provides access to

    slice3[] = slice1;    // ← the values of the elements of
                          //   slice3 change

    writeln("slice1 before: ", slice1);
    writeln("slice2 before: ", slice2);
    writeln("slice3 before: ", slice3);

    slice2[0] = 42;       // ← the value of an element that
                          //   it shares with slice1 changes

    slice3[0] = 43;       // ← the value of an element that
                          //   only it provides access to
                          //   changes

    writeln("slice1 after : ", slice1);
    writeln("slice2 after : ", slice2);
    writeln("slice3 after : ", slice3);
}

slice2指向一些数据，然后改为指向别的东西，这不会导致内存泄漏吗？

Answer 1

D是垃圾收集语言。垃圾收集器最终可能会释放为无法访问的对象分配的内存。