我正在尝试解析日志文件并将其转换为.csv文件。我在分割功能方面遇到了麻烦。例如,我在日志文件中有以下内容: 21a94551,00:00:59.643;错误; 。当我尝试拆分逗号(,)和半冒号(;)时,我从输出csv文件中的时间戳中丢失.643。我想保持时间(00:00:59.643
)不变。我在日志文件中有多行(所有行都有不同的数字),因此这些值不明确。
当我在分割功能后使用打印功能时,值会输出到屏幕确定,但在CSV文件中
我是Perl的新手。有人可以解释一下我做错了什么吗?我认为问题可能在于如何处理字符串?
use strict;
use Cwd;
use Excel::Writer::XLSX;
use Text::CSV_XS;
use Spreadsheet::Read;
my $dirname = getcwd; # Set the directory to current working directory.
opendir (DIR, $dirname) || die; # Open the current directory
my @FileNameList = readdir(DIR); # Load the names of files in to an array
foreach (@FileNameList) #Read each of the file names
{
my $FileName = $_;
my $Output;
if ($FileName =~ m/iusp_\d+.log/)
{
print ("\n". $FileName." \n Correct Log File Found");
open (my $file, "<", $FileName);
while (<$file>) {
chomp; # Remove the \n from the last field
my $Line = $_; # Create the variable SLine and place the contents of the current line there
if ( $Line =~ m/ERROR/ ) # Select any line that has "ERROR" inside it.
{
my @fields = split /[,;]/, $Line; # Split up the line $Line by ", ;"
my $csv = Text::CSV_XS->new(); # Create new CSV
$csv->combine(@fields);
my $csvLine = $csv->string();
print $csvLine, "\n";
{
$Output = $csvLine . "\n";
}
my $OutputFileName = $FileName . ".csv";
print( "\n Saving File:" . $OutputFileName );
open( MyOutputFile, ">>$OutputFileName" );
print MyOutputFile $Output;
} #End of IF Statement
} #End of while statement
答案 0 :(得分:6)
简化你的正则表达式。您不需要.*
(perldoc -f split)。点被split
视为分隔符,因为它位于字符类方括号内。
use warnings;
use strict;
use Data::Dumper;
my $Line = '21a94551,00:00:59.643;ERROR;';
my @fs = split /[,;]/, $Line;
print Dumper(\@fs);
__END__
$VAR1 = [
'21a94551',
'00:00:59.643',
'ERROR'
];
答案 1 :(得分:2)
[]
内的内容不是正则表达式,它是一组字符或字符范围或类。当您只想分开,
或{{1}时,您已告诉它要分为.
或*
或;
或,
}:;